So I think I have found a way to get the two outer components by using trig to get the lengths then multiplying by the force. I end up with 3*4sin35 5*4sin55 but still unsure of how to get the moment of the middle 5N component?
So I think I have found a way to get the two outer components by using trig to get the lengths then multiplying by the force. I end up with 3*4sin35 5*4sin55 but still unsure of how to get the moment of the middle 5N component?
You should resolve the distances rather than the force. Remember that torque = force x perpendicular distance from the pivot. Find the perpendicular distance from the point P to the line of action of each force using right angled trigonometry.
You should resolve the distances rather than the force. Remember that torque = force x perpendicular distance from the pivot. Find the perpendicular distance from the point P to the line of action of each force using right angled trigonometry.
I think that is what I did? but I am not entirely sure haha
I drew the lines to the forces (perpendicular distance) then used trig to get the lengths of 4sin35 & 4sin55, although (and I may just be thick) I can't seem to find the length for the middle force?
I think that is what I did? but I am not entirely sure haha
I drew the lines to the forces (perpendicular distance) then used trig to get the lengths of 4sin35 & 4sin55, although (and I may just be thick) I can't seem to find the length for the middle force?
You've 2/3rd of the work done then
Extend the line of action of the 5 N force like I've done in the diagram (the white dotted line):
Diagram
The red line is the perpendicular distance from the pivot P to the line of action of 5 N.