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Proving SUVAT Equation June 2009

Attached is a graph of velocity against time.
My question is to prove that

s = ut + 1/2at^2

I start by finding the area of the rectangle, knowing that the area under the line gives displacement.

s = ut

I then find the area of the triangle

1/2 (v-u) * t

= 1/2 * at * t
= 1/2at^2

So I thought that the rectangle - area gives the area
being s = ut - 1/2 at^2

but why is this not the case?
Screen Shot 2016-04-20 at 20.10.01.png23.8KB
Reply 1
Avatar for nwmyname
nwmyname
OP
13
Update - i am so silly sorry i noticed the mistake.
Original post by nwmyname
Attached is a graph of velocity against time.
My question is to prove that

s = ut + 1/2at^2

I start by finding the area of the rectangle, knowing that the area under the line gives displacement.

s = ut

I then find the area of the triangle

1/2 (v-u) * t

= 1/2 * at * t
= 1/2at^2

So I thought that the rectangle - area gives the area
being s = ut - 1/2 at^2

but why is this not the case?


you're trying to do this...

sequalsutplushalfatsquared.png
Reply 3
Avatar for nwmyname
nwmyname
OP
13
Original post by Joinedup
you're trying to do this...

sequalsutplushalfatsquared.png


I know haha I looked at it from completely the wrong way!

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