Chem oxidation ques
For part A, can't lithium be an answer as well because it gets oxidised from +1 to +2?
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Original post by Pigster
Li 1s2 2s1
Li+ i.e. oxid. state +1 1s2
Li2+ i.e. oxide state +2 1s1 NO WAY HOSE
Co is your man.
Li+ i.e. oxid. state +1 1s2
Li2+ i.e. oxide state +2 1s1 NO WAY HOSE
Co is your man.
Yeah but lithium is getting oxidised as well!!
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Original post by Lilly1234567890
There's no way you could take another electron from Li+.
Hi Lily1234567890
The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.
Li+ + CoO2 + e- --> Li+(CoO2)-
Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.
I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.
Alex
The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.
Li+ + CoO2 + e- --> Li+(CoO2)-
Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.
I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.
Alex
Original post by ajsullivan
Hi Lily1234567890
The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.
Li+ + CoO2 + e- --> Li+(CoO2)-
Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.
I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.
Alex
The answer is Co. The question tells you the HALF equation that takes please at the positive electrode.
Li+ + CoO2 + e- --> Li+(CoO2)-
Here the cobalt is changing oxidation state from +4 to +3 so it is being reduced. The Lithium in the previous equation is going from an oxidation state of 0 to +1 and is therefore being oxidised.
I think you MAY be getting confused with oxidation state and oxidised? Either way I hope that helps.
Alex
O yea got it now after reading question again! Thanks !
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