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Log equation, i need help

logyx = 3
log3x-log3y = 5

I have to find exact values for x and y but i don't know where to start
Reply 1
Avatar for sabana
sabana
20
From equation 1, y^3=x so sub this into equation 2.
Original post by sabana
From equation 1, y^3=x so sub this into equation 2.
thanks, i think i get it now :smile:
Reply 3
Avatar for sabana
sabana
20
That would give you log3 (y^3÷y) = 5
Reply 4
Avatar for sabana
sabana
20
Then finally remove logs
Reply 5
Avatar for sabana
sabana
20
Original post by confusedlemur99
thanks, i think i get it now :smile:


No problem :h:
Original post by sabana
Then finally remove logs


i got Y to be 9*square root of 3
is that right?
Reply 7
Avatar for Zacken
Zacken
22
Original post by confusedlemur99
i got Y to be 9*square root of 3
is that right?


Yes.
Original post by Zacken
Yes.


thanks :smile:
Reply 9
Avatar for sabana
sabana
20
Original post by confusedlemur99
i got Y to be 9*square root of 3
is that right?


Yes

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