The first three terms in ascending powers of x in the binomial expansion of (1 + px)12 are given by 1 + 18x + qx2 where p and q are constants. Find the value of p and the value of q.
Use binomial theorem to find value of p - there can only be one value of p to give the coefficient of the x term to be 18. And from there you find q. (1+px)12=1+(121)px+(122)(px)2+⋯+(px)12.
Use binomial theorem to find value of p - there can only be one value of p to give the coefficient of the x term to be 18. And from there you find q. (1+px)12=1+(12c1)px+(12c2)(px)2+⋯+(px)12.
So I used binomial expansion and got...... 1+12px+66p^2x^2 . Now what?