Physics AS Specimen Paper. Wtf do I do. This is scaring tf out of me.
A student has a diffraction grating that is marked 3.5 * 10^3 lines per m.
Calculate the percentage uncertainty in the number of lines per metre suggested by this marking.
FREAKING WOT M8. Okay but on a serious note.. how do I know what the uncertainity. I feel like it has something to do with number of sig figs they give the value to. Pls help.!
Calculate the percentage uncertainty in the number of lines per metre suggested by this marking.
FREAKING WOT M8. Okay but on a serious note.. how do I know what the uncertainity. I feel like it has something to do with number of sig figs they give the value to. Pls help.!
Original post by cleggj88
(100/3.5*10^3)*100
=2.9%
this should be it, check the mark scheme
=2.9%
this should be it, check the mark scheme
Could you explain it? Why is the uncertainity 100?
Original post by Someboady
Could you explain it? Why is the uncertainity 100?
It rounds to 3.5*10^3, so the true value lies in the interval 3.45*10^3<x<3.55*10^3. Therefore the uncertainty is +-50, =100 total
Original post by samb1234
It rounds to 3.5*10^3, so the true value lies in the interval 3.45*10^3<x<3.55*10^3. Therefore the uncertainty is +-50, =100 total
Wait so isnt the uncertainty +- 0.05 = 0.1? :/
Original post by Someboady
Wait so isnt the uncertainty +- 0.05 = 0.1? :/
+-0.05*10^3 =50
Original post by samb1234
+-0.05*10^3 =50
All this for one mark? *cries*
Thanks a bunch!
Original post by Someboady
All this for one mark? *cries*
Thanks a bunch!
Thanks a bunch!
no problem, let me know if you have any other issues
Original post by samb1234
It rounds to 3.5*10^3, so the true value lies in the interval 3.45*10^3<x<3.55*10^3. Therefore the uncertainty is +-50, =100 total
This is right
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