Urgent maths help plz

so first you need to work out the area of the trapezium which is: The two widths added and divided by 2 multiplied by height. (1.4+3)/2 x 2.4. = 5.28
use that area to work out the volume of the whole thing. So 5.28 x 2.5 (height) =13.2m^3.
Each m^3 = 1000l therefore you have 13200 to fill (as 13.3x1000=13200). However, you only want 85% so you do 13200x0.85=11220 which is 85% of the whole volume.
Then you do 11220/300 to get how long it will take to fill...

edit: Oops, someone submitted an answer as i was still typing mine! it's still below, anyway.

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right.

You need to work out the volume of the tank.

Volume of tank = cross-sectional area * depth

cross-sectional area in cm^2 = 240 * (300 + 140)/2
= 240 * 220
= 52,800
[area of a trapezium]

volume in cm^3 = 52,800 * 250
= 13,200,000

volume in litres = 13,200,000 / 1,000
= 13,200

volume to fill in litres = (0.85 * 13,200) - 300
= 10,920
[because 85% needs to be filled, and 300 litres already filled]

time in minutes = volume to fill / volume filled per minute
= 10,920 / 300
= 36.4

Edit: Oops, someone submitted an answer as I was still typing mine! It's still below, anyway.

================

Right.

You need to work out the volume of the tank.

Volume of tank = cross-sectional area * depth

Cross-sectional area in cm^2 = 240 * (300 + 140)/2
= 240 * 220
= 52,800
[area of a trapezium]

Volume in cm^3 = 52,800 * 250
= 13,200,000

Volume in litres = 13,200,000 / 1,000
= 13,200

Volume to fill in litres = (0.85 * 13,200) - 300
= 10,920
[because 85% needs to be filled, and 300 litres already filled]

Time in minutes = volume to fill / volume filled per minute
= 10,920 / 300
= 36.4

Can you answer the next question! Plz I beg!!!