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OCR MEI Maths - C1 - help

How do i do 13 iii) - i don't get it :/
write

x4 - 2 = kx2

investigate the Discriminant... this tells you how many roots the equation has.
Reply 2
Original post by the bear
write

x4 - 2 = kx2

investigate the Discriminant... this tells you how many roots the equation has.


Discriminant = b^2 - 4ac

....Stuck. What do i do with the x^4?
Original post by tmifan
Discriminant = b^2 - 4ac

....Stuck. What do i do with the x^4?


this is a disguised quadratic...
Reply 4
Original post by the bear
this is a disguised quadratic...


So its just:
(-k)^2 - (4 x 1 x -2)

= -k^2 + 8

Then?
Original post by tmifan
So its just:
(-k)^2 - (4 x 1 x -2)

= -k^2 + 8

Then?


discriminant = k2 + 8

what does that tell you ?
Reply 6
Original post by tmifan
So its just:
(-k)^2 - (4 x 1 x -2)

= -k^2 + 8

Then?


(k)2=k×k=1×k×1×k=1×1×k×k=1×k×k=k2(-k)^2 = -k \times -k = -1 \times k \times -1 \times k = -1 \times -1 \times k \times k = 1 \times k \times k = k^2.
Reply 7
Original post by the bear
discriminant = k2 + 8

what does that tell you ?


...I don't know...
(edited 7 years ago)
Reply 8
Original post by tmifan
...I don't know...


What does the discriminant always being greater than 0 mean?
Reply 9
Original post by Zacken
What does the discriminant always being greater than 0 mean?


2 roots!

but how do you know its greater than 0...from k2 + 8
Reply 10
Original post by tmifan
2 roots!

but how do you know its greater than 0...from k2 + 8


Well what do you know about a squared number? What do you get is you take a squared number and add a positive number?

If you cannot answer that, then think about what is (-100)^2 - what is (-200)^2 - what is (1)^2, what do they all have in common?
Reply 11
Original post by Zacken
Well what do you know about a squared number? What do you get is you take a squared number and add a positive number?

If you cannot answer that, then think about what is (-100)^2 - what is (-200)^2 - what is (1)^2, what do they all have in common?


Oh duhh! sorry that was a stupid question

Okay i get it now! Thank you both!

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