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Help C2 Question

can someone explain the second part
ma1.PNG
Reply 1
Avatar for Zacken
Zacken
22
Original post by mh99
can someone explain the second part
ma1.PNG


2πa\frac{2\pi}{a} is the period of the graph, what's the period of the graph from the coordinates? Equate those two to find a. Then just sub in a point to find b.
Reply 2
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mh99
OP
9
Original post by Zacken
2πa\frac{2\pi}{a} is the period of the graph, what's the period of the graph from the coordinates? Equate those two to find a. Then just sub in a point to find b.


Thanks this make more sense now but how did you find the period of graph at the start
Reply 3
Avatar for Zacken
Zacken
22
Original post by mh99
Thanks this make more sense now but how did you find the period of graph at the start


Function transformations. f(ax)f(ax) compresses the graph of f(x)f(x) by a units.

So since the period of the sine graph is f(x)=sin⁡xf(x) = \sin x is 2π2\pi then the period of the squashed sine graph f(ax)=sin⁡(ax)f(ax) = \sin(ax) has period 2πa\frac{2\pi}{a}. The translate of +b does not affect the period.
Reply 4
Avatar for mh99
mh99
OP
9
Original post by Zacken
Function transformations. f(ax)f(ax) compresses the graph of f(x)f(x) by a units.

So since the period of the sine graph is f(x)=sin⁡xf(x) = \sin x is 2π2\pi then the period of the squashed sine graph f(ax)=sin⁡(ax)f(ax) = \sin(ax) has period 2πa\frac{2\pi}{a}. The translate of +b does not affect the period.


Okay, Thanks :smile:
Reply 5
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Zacken
22
Original post by mh99
Okay, Thanks :smile:


No problem! :smile:

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