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AQA C1 Unofficial Markscheme

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Original post by money-for-all
i got y=8 and my skecth was an upside down quadratic graph like an upside down 'U' is that right ? or nah


Yeah, sounds right.

quad.png
Reply 101
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Original post by AccountingHelp
If I'm thinking about the same question as you, you didn't have to work out the max point did you? It just said state clearly the y intercept


Oh, sorry. Yep, I meant intecept. So is it at y=15?
Original post by df97
Shouldn't it be 75-32rt5?


Yep, thanks! What a big change one button press can be! I've edited the original post. Sorry to anyone I confused!
Screenshot from 2016-05-18 14-34-23.png14.1KB
hey i messed up some how on the last step of finding equation of P ( used the right method) meaning i got point Q wrong and so forth couldnt work out the area! but i got the correct integral and the correct method throughout and so how many marks will i loose for this whole section??
Original post by 28657
Oh, sorry. Yep, I meant intecept. So is it at y=15?


No, y=8
quad.png18.5KB
Reply 105
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Original post by timtjtim
Yeah, sounds right.

quad.png


****, here goes -1 mark
Reply 106
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Original post by BlackthornRose
Exactly what i was thinking.



So the translation was [1/2, 41/4] as opposed to [1/2, -41/4]? Please explain, i sort of understand and sort of don't as i can't completely remember which one it said is supposed to map onto the other.


The question was y=(x-7/2)-41/4 to y=(x-4)
So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
Hope that helps :smile:
what was the question in number 3, 4, 6, 7a 7b, 8a
Reply 108
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..
(edited 7 years ago)
Who else got root 34 ? Please say aye aye captain !
Original post by money-for-all
Who else got root 34 ? Please say aye aye captain !


sorry thats wrong lol the radius is root 65
Original post by money-for-all
Who else got root 34 ? Please say aye aye captain !


nope :frown:

root 65 :smile:
Original post by timtjtim
Yeah, sounds right.

quad.png


What a g, you drew what I did, I knew AQA were trying to be sneaky so I completed the square on the quadratic and found out that it turns above 8 and drops down to pass through the 8 (y-intercept), rate you for it aha
Original post by BearackObama
How did people get root 65 for the radius of the circle when the centre co-ordinates were (5,-3). On expanding this came out as root 34 surely?


i got rooooooooooot 34
Original post by df97
The question was y=(x-7/2)-41/4 to y=(x-4)
So we need to get rid of the -41/4, to do that we need to add -41/4 to LHS.
Vector [a,b] translates y=x to y-b=x-a therefore [1/2, 41/4] must give y-41/4=(x-7/2-1/2)-41/4 clearing it up gives y=(x-4)
Hope that helps :smile:


Yes it did, thank you very much. I also just reworked it out for myself and you are correct. That's another mark gone for me.
I recently made a new thread with an updated mark scheme if you lot could add to it, it will be finished soon

http://www.thestudentroom.co.uk/showthread.php?t=4095491
(edited 7 years ago)
Original post by timtjtim
No, y=8


did you have to mention the x cordinates ?!?!?!?!?
Original post by money-for-all
i got rooooooooooot 34


Mate you had to use the distance formula or place the number in the eq to find k (=r^2)
Original post by rndmtngr99
I got k=30:h:

Are u sure k wasn't -30
Reply 119
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Original post by beanigger
sorry thats wrong lol the radius is root 65


I got sqrt65 as well. Did you find it by using pytharogas or substituting point A into the equation?

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