C1 Maths AS aqa 2016 (unofficial mark scheme new)

Yh thats what i got. Thanks god lol. I think it was q8 as q7 was the intergration section

to get 100 ums, is 75/75 marks usually required?

For the one where you had to prove it was a minimum value, I believe you first need to find that it is a stationary point by subbing in to dy/dx, then subbing in to d^2y/dx^2 to show it is a minimum.

I base this on the fact the question was 4 marks, and it wouldn't be 4 marks for only subbing in to d^2y/dx^2.

anyone remember how the question where they asked to show that it was a decreasing function?

My estimate is 73 for 100UMS on this paper. Usually its 74, but I feel there were many rooms for mistakes on this paper.

My estimate is 73 for 100UMS on this paper. Usually its 74, but I feel there were many rooms for mistakes on this paper.

The q 'stated' (x-a)^2 + (y-b)^2 = k
where 'k' = r^2 = 65
anyone who put sqroot65 is wrong and would of lost 1 mark

Wait, are we 100% positive the first question asked for a parallel line? I could have sworn it said perpendicular and gave 5/3 as my gradient...

Could you include how many marks each question is work. I think Question 1) 2
2) 5

it said parallel to the curve

this is exactly what I thought but I tried putting the value into dy/dx like twice and I couldn't get zero so I just left it :/



I think it was part of the question I just quoted

****. I can't remember how much of the rest of question 1 is screwed up by this now. I thought I had around 71/75, so much for that.

I subbed point P, x coordinate into dy/dx and got 0 and said that it was a decreasing function. It is the x- coordinate of P right ?

Unoffical Mark scheme for C1 AQA 2016

It would help if you could link answers to questions as i cant remember them

Questions
1) a)Asked to work out gradient of a tangent, m= - 5/3 [2]
b)Asked to find co-ordinates of B B( - 3,4) [3]
c)Asked to find K K= - 30 [2]

2) a) simplify (3√5)^2 = 45 [2?]
b) i cant remember the question but the answer was 75 - 32√5 [5]

3) a) y=(x-7/2)^2 - 41/4
b) min value = -41/4
c) Translation of (1/2 , 41/4)

4) a) show that (x+3) was a factor of x^3 - 5x^2 -8x + 48, p(-3) = 0, (x+3) is a factor of p(x).
b) three linear factors of p(x) = (x+3)(x-4)(x-4)
c) find remainder when p(x) was divided by (x+2) R=20
d) Factorise p(x) using (x+2) R = (x-2)(x^2-3x+14) + 20 [3]

5) a) asked to find equation of circle (x-5)^2+(y+3)^2=65 (note 65 = r^2) [3]
b) asked to find co-ordinates of B (AB is diameter) B ( 12, -7) [2]
c) asked to find equation of tangent at A 7x-4y+18=0 [5]
d) asked to find length of CT = 9 [2]

6) a) y=-32x-40
b)Q(-5/4) [1]
c) upside down positive graph passing through y axis at 8 [2]
d) x = -1±√5

7) a) i think there was 4 parts to this question i cant remember part a and b
b)
c) definite integral = 81/4 [5]
d) area of shaded region = 45/4 [3]

8) a) cant remember anything except the answers were k>6 and k<-3/2

Answers that need a question to be assigned to
- k=4 and k=20
- d^2y/dx^2= - 2x - 9x^2 sub in x-coord of p to get 45, 45>0 therefore minimum

yes you use the x coordinate of p
I put dy/dx <0, then put in P and showed it was less than zero and therefore decreasing

on one of the questions P was (-2,24) idk if it's the same one and might trigger someone's memory on the rest of the question

Wait, are we 100% positive the first question asked for a parallel line? I could have sworn it said perpendicular and gave 5/3 as my gradient...

Nope pretty sure the top students in my Sixth Form got root65 as the radius

Its root 64