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CCEA AS Maths- C1 Wed 18th May

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Reply 20
Original post by aoifea100
I think the issue with that question was that it cancelled to 2-X whereas the other bracket was 3x - 6, so most people probably didn't realise to take -3 out instead of a positive 3?
A lowered grade boundary would be amazing:biggrin:

Instead of 2-x I did -(x-2) which cancelled when you took three out of (3x-6) to get 3(x-2). We ended up with the same answer though
Reply 21
Original post by ozmo19
@aoifea100


Did anyone get the same answers as these?

1)2-√5

2)i) (2,4)
ii) (4,3)
iii) a= -4

3)x= (7/2)

4)a) -1/(3x)
b) (2,3)

5)ii) (x+4)(2x-3)(x-6)
b)c= -3/2

6)a)a= -1, b= -8
b)ii) x+12y-44=0

7)ii)w=15cm, h=20cm
8)a)(1-3√5)/2 k (1+3√5)/2
b) b^2 -4c = 1


I think most of ours correlates, if I remembered the question I would be able to help.

When I saw the rationalise the denominator first question, I thought we were in for a good one!



Yes, low grade boundaries are a must!
I'm guessing I got around 60-65 does anyone have a clue what that would roughly be?


Posted from TSR Mobile
Original post by ozmo19
@aoifea100

Did anyone get the same answers as these?

1)2-√5

2)i) (2,4)
ii) (4,3)
iii) a= -4

3)x= (7/2)

4)a) -1/(3x)
b) (2,3)

5)ii) (x+4)(2x-3)(x-6)
b)c= -3/2

6)a)a= -1, b= -8
b)ii) x+12y-44=0

7)ii)w=15cm, h=20cm
8)a)(1-3√5)/2 k (1+3√5)/2
b) b^2 -4c = 1



can you post a solution to 7i and 6a! Can't remember the qu for 6a and I'm going round in circles still for 7i!!! Thanks for posting answers is put my mind t ease!!!
Reply 24
Original post by Sparklez10
can you post a solution to 7i and 6a! Can't remember the qu for 6a and I'm going round in circles still for 7i!!! Thanks for posting answers is put my mind t ease!!!


Ill talk you through the method
for 6a
you find dy/dx and equal it to 0
Sub in x=2 and get an equation
Sub in x=-4/3 and get an equation
Solve simultaneous equations.

for 7i
[(40x30)/2] = wh + 0.5 x w x (40-h) + 0.5 x h x (30-w) (i think)
rearrange for h
you end with h=40 - (4w/3)
Then A=wh so sub in h.
Okay thank you so much! I have got method marks for both but just couldn't get the final answers!
do you reckon grade boundaries will be high??
Reply 26
Original post by Sparklez10
Okay thank you so much! I have got method marks for both but just couldn't get the final answers!
do you reckon grade boundaries will be high??


No, i think they'll be relatively low, or so I'm hoping they are!
Reply 27
Original post by John5678
Hows everyone feeling for C1 Maths for CCEA tomorrow?

Hadn't seen a CCEA thread, so decided to make one!


First time I hear about this board!
:biggrin:
Reply 28
Original post by M14B
First time I hear about this board!
:biggrin:


Its a Northern Irish board
Reply 29
Original post by M14B
First time I hear about this board!
:biggrin:


Solely Northern Irish board!
Reply 30
Original post by John5678
@lmg1 @ozmo19


How did yous find it? All was good at the start; q7 the proof was dodgy, I didn't get the final answer; but most of my working was broadly similar, so hopefully a few marks there.
Q8 ii I think, where b2-4c = n and (n+1) was such a dodgy question, didn't have a clue there.
Other than that, not bad- but definitely on the hard side.


Your thoughts on how it went?


It wasn't that bad, it could've went a lot worse
Reply 31
Original post by ozmo19
Ill talk you through the method
for 6a
you find dy/dx and equal it to 0
Sub in x=2 and get an equation
Sub in x=-4/3 and get an equation
Solve simultaneous equations.

for 7i
[(40x30)/2] = wh + 0.5 x w x (40-h) + 0.5 x h x (30-w) (i think)
rearrange for h
you end with h=40 - (4w/3)
Then A=wh so sub in h.


Would I lose a lots marks because in Q.6a I multiplied out -4/3 to get -4 and subbed this into equation and for final answers I got -3 and -8. I completely forgot to divide it by 3.
Original post by ozmo19
No, i think they'll be relatively low, or so I'm hoping they are!


What do you think the A will be??
Reply 33
Original post by aoifea100
@ozmo19 yeah most of these answers look similar, definitely glad you got that -1/3x, I thought I messed that up a lot
For 8a I did it < in place of which I know is wrong now, but I got the same answer so I should at least get most of the marks for that part
Everything but 8b looks the same as what I got


I done exact same thing for Q.8a even though I had only revised it that morning but I got the right answer. For the question about the product of linear factors how many marks would you lose for forgetting to add (x+4)?
I have to admit going through the paper I lost a few stupid marks but my working out was mostly fine (except for Q8b).
Reply 34
Original post by Sparklez10
What do you think the A will be??


It would probably be similar to last years paper. Do you know what the grade boundaries were for June 2015.
Reply 35
image.jpeg
Does anyone have a solution for this?
Original post by lmg1
It would probably be similar to last years paper. Do you know what the grade boundaries were for June 2015.


I'm not sure sorry! I will ask around and see!! How did you find it
Could you please put up the method you did for 8 part b?
Original post by ozmo19
image.jpeg
Does anyone have a solution for this?


I did get 1 but I can't remember how I got it exactly. But to start with I did that b^2-4C>0
that paper effed me up lol

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