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Edexcel International A level (IAL): Physics Unit 6 (WPH06) - 19th May, 2016 - PM

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Original post by Aimen.
oops yea it was cx/gradient , I did a mistake up there!


Alright. Well, i wrote V2 = 1/cy x Cx(v2-v1)

V2 as y -axis

Inverse of gradient is the value of Cy

and Cx(Net "V") as Y-axis.

The value of C intercept is zero because its straight line graph NOT LINEAR !

*It was mentioned in the question that how would a straight line graph would you form!
Original post by WilsonDS
Q4: I forgot to convert Celsius into Kelvinfffffffffuuuuuuuuu :frown:


same how many marks do u think we lose? + the curve was terrible haha
Original post by abdullakhalaf
same how many marks do u think we lose? + the curve was terrible haha


Maybe the entire marks from Q4 :'( NotLikeThis
Reply 163
Avatar for AvWOW
AvWOW
3
Original post by ab9826
i got the time period as 3.20 seconds and the next question about the equilibrium as 0.80 seconds. Are any of these correct? for the uncertainty in the first question i got 2.2%


I got the same answers for the period and same value. Dunno about the uncertainty thing.
Reply 164
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AvWOW
3
Original post by Aimen.
I wrote repeat and average after cooling the setup!

That would have been a smarter move :/
Original post by apocolyptic
what do u guys think


Yep, It seems that this time the paper, had kinda a different format than most of the former papers T_T
Original post by Aimen.
oops yea it was cx/gradient , I did a mistake up there!


Hey I did the same thing..V1 on y axis and Vx on x axis..then Cy/Cx was gradient ..so Cy= gradient *Cx
Shouldnt we put V1 on y axis since we are gonna vary it..I think both the ways will be marked correct
Original post by Choudhry Walid
Alright. Well, i wrote V2 = 1/cy x Cx(v2-v1)

V2 as y -axis

Inverse of gradient is the value of Cy

and Cx(Net "V":wink: as Y-axis.

The value of C intercept is zero because its straight line graph NOT LINEAR !

*It was mentioned in the question that how would a straight line graph would you form!


V1 against V2 is wrong? That gives the opposite gradient i.e. Cy/CxThen Cy =gradient*Cx
Original post by Sandy_Vega30
Did anybody get the acceleration at 0.4 s to be 1.96 ms^-2 ?


I got 1.94 ms^-2
Original post by tgygt
How about precaution for the capacitor question?

Check the capacitor's polarity. They must be connected in the right way to the battery.
or
The capacitors' must be rated at least to the maximum emf of the power supply. Otherwise they may get damaged.
Original post by WilsonDS
Maybe the entire marks from Q4 :'( NotLikeThis


wait the question to prove a straight line was worth 2 so we get that, and don't we get points for scales and plotting, and drawing a line of best fit? so that should be 2. also how many marks was the whole q worth?
is there no link to the paper?
Reply 172
Avatar for Aimen.
Aimen.
7
Original post by RizK
Correct. Acceleration is proportional to displacement: at t=0.80s, (wait not v=0.80ms^-1) its at center oscillation - displacement is zero so acceleration is zero and the tangent (dv/dt) = zero

I screwed up everything else tho. ggwp


Haha yea I meant t=0.80 s, v was sumfin like 1.40?
Reply 173
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tgygt
2
Hey guys, where do you do your rough work for physics? Is there any rough work sheet?
Original post by andreashadj99
Check the capacitor's polarity. They must be connected in the right way to the battery.
or
The capacitors' must be rated at least to the maximum emf of the power supply. Otherwise they may get damaged.



Well, I wrote that use a fixed resistor to protect the capacitor from damaging when the resistance of the whole circuit is zero.
Original post by Choudhry Walid
Well, I wrote that use a fixed resistor to protect the capacitor from damaging when the resistance of the whole circuit is zero.


Not sure if this is going to be acceptable. Also my second answer
"The capacitors' must be rated at least to the maximum emf of the power supply. Otherwise they may get damaged."
is incorrect since we do not know the capacitance of the capacitor Y.
(edited 7 years ago)
Original post by AvWOW
I got 1.95x10^-19 for the charge.... everyone seems to have gotten something along the line of 1.55x10^-19
O_O pooping bricks here


i got something like 1.49
In no. 4 possibly everything was right except that i forgot to multiply 10^-3 with the temperature while calculating p and so the answer was 3.45 rather than 3450. The next two answers were right except that i took the wrong value. Does anyone have any idea whether i will get marks for the rest two i mean the vaue of e and comment about accuracy or not?
Original post by Mahdia Akter
In no. 4 possibly everything was right except that i forgot to multiply 10^-3 with the temperature while calculating p and so the answer was 3.45 rather than 3450. The next two answers were right except that i took the wrong value. Does anyone have any idea whether i will get marks for the rest two i mean the vaue of e and comment about accuracy or not?


You will.
Original post by ali shahid1
I got 2 ms^-2

same, i got 2

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