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<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>
<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>
<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>

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Reply 60
Avatar for LukeB98
LukeB98
4
It was mostly the small things that tripped me up, like 6(e), I didn't expressly state R=R^-1.
Question 7 was ****ed, if you couldn't get a... quite harsh from the exam board no? I'm sure there'd be carry through marks.
7(e) wasn't nice,
8(i) took me a while to spot and my proof looks pretty shoddy, dunno how convincing to the examiner...
9(c)
Hi, for 7(e) I was wondering if this answer is accepted?

Line QR is the image of line OP under an enlargement of scale factor 2 with centre (0,0) followed by translation (-3,-4)
For part (a) of the summation series question, (the 1 marker) I put
... 3n/6(3n+1)(6n+1) would that get me the mark? Thanks
Reply 63
Avatar for ombtom
ombtom
17
Original post by TrueDAN
Everyone commenting top 60s and 70s and I think I've came in with a low blow in the 50s :frown: Really disheartened by it, I guess we all have a bad test though. I predict I will have a D/C which sucks, really thought I had this module down. Damn, I guess we all have a bad test though, will definitely resit it, congrats to all you geniuses getting these insane marks!


People who didn't get a high mark are less likely to post what they got. Don't worry about it. :smile:
Original post by CostaMiyagi
Thank you Arsey! 61/75 not too bad :smile:


we got the same marks i think, hoping that this is an A!
I did Worse than I thought, 67/75.
Original post by CostaMiyagi
Thank you Arsey! 61/75 not too bad :smile:



we got the same marks i think, hoping that this is an A!
Original post by iMacJack
Daddy Donny will be proud enough - at least we did a harder paper than Ivan and did better


what was the best uni he got an offer from surry? Because at least we know we can get there
Original post by NoahMal
what was the best uni he got an offer from surry? Because at least we know we can get there


Lol yeah with a bit of luck maybe
Original post by hogree
Midpoint is always (a+b)/2 not (a-b)/2

Posted from TSR Mobile


Hmm I see what I was trying to do. I found the distance of x and y from A but forgot to add it to the coordinates of A..... Excuse me while I go shoot my foot
(edited 7 years ago)
Original post by ilovetacobell
we got the same marks i think, hoping that this is an A!


Should be if everyone is finding it hard :smile:
Reply 71
Avatar for kewjing
kewjing
1
Original post by Arsey
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits


May I ask question, I did qp=-1 then q=-1/p so the gradient of q become -p. The gradient of p is 1/p. And I state because they are inverse function so they are perpendicular(can't remember what I exactly said) can I still get the mark?
Reply 72
Avatar for TeeEm
TeeEm
19
Quick poll on
http://www.thestudentroom.co.uk/showthread.php?t=4101989
max lost 10 marks , is that an A?
Original post by kewjing
May I ask question, I did qp=-1 then q=-1/p so the gradient of q become -p. The gradient of p is 1/p. And I state because they are inverse function so they are perpendicular(can't remember what I exactly said) can I still get the mark?


Well here's what I did;

pq = -1 from the previous part

1/p = grad of tangent at p
therefore grad of tangent at q = 1/q

So for them to be perpendicular the product of the gradients = -1

1/p * 1/q = 1/pq = -1 as pq = -1 from the previous part
Reply 75
Avatar for kewjing
kewjing
1
Original post by Pyslocke
Why is the midpoint of AP (5p - 5/p + 5p) / 2?

Why isn't it [5p - (-5/p +5p)] / 2 = 5/2p.

Am I going mad again?


EDIT: I know that using this method I get p = 0 so x would be undefined as shown. But I was still lost


midpoint is (x1+x2)/2 (y1+y2)/2
Original post by kelvin1338
Hello Arsey,

For the sequence induction question, do I have to prove it's true for n=2 as well? Would I have lost a mark in not doing so?


Could you please tag me when he answers? Thanks
Reply 77
Avatar for kewjing
kewjing
1
Original post by iMacJack
Well here's what I did;

pq = -1 from the previous part

1/p = grad of tangent at p
therefore grad of tangent at q = 1/q

So for them to be perpendicular the product of the gradients = -1

1/p * 1/q = 1/pq = -1 as pq = -1 from the previous part


Can I still get the mark if I just compare two gradient as m1=-q and m2=1/q
Original post by kewjing
Can I still get the mark if I just compare two gradient as m1=-q and m2=1/q


How did you get to that point?
Anybody have any ideas of grade boundaries, I think I might of just scraped an A which is good for me coming from a mid C from last years paper.

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