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Mr M's OCR (not OCR MEI) Further Pure 1 Answers May 2016

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Mr M do you have a rough opinion of what the grade for an A may look like?
Original post by Mr M
I expect so. I think this will be a very common mistake.


how many would i drop in part 8.ii for missing the 2n on top?
Original post by anon326589
why root5 for 6i)?

Also how do you 10iii)?

Thanks in advance


Because the diameter is 252 \sqrt 5 !

You do 10iii) by understanding the connection with 10ii) and 10i).
(edited 7 years ago)
Original post by emilyp2206
Just wondering how many marks i would lose for:

7ii) somehow fluffed up my matrix and got

-3 8
0 3

or something, but correctly described what it was and showed methods and everything of how i got there

10ii) didnt do or really even imply over 41 (not sure how i missed that), i identified conjugate root and then the roots of those


7ii) I can't see any marks there but the working on your script might get you something.

10iii) You've probably got 2 marks there.
Original post by proximity
Mr M do you have a rough opinion of what the grade for an A may look like?


I don't like to guess boundaries.
Reply 25
Avatar for S.G.
S.G.
22
Original post by ComputeiT
Thanks again for your answers - would you get ECF for the sum to infinity if you forgot to half the method of differences from 8 part ii?


Wait, why would you half?
Original post by Mr M
Because the diameter is 2sqrt52 sqrt 5 !

You do 10iii) by understanding the connection with 10ii) and 10i).


oh so you don't include i in the calculation

only just spotted the connection

thanks
Original post by ComputeiT
how many would i drop in part 8.ii for missing the 2n on top?


Probably just 1.
Original post by SGHD26716
Wait, why would you half?


You were summing half of the expression you derived in i).
Original post by SGHD26716
Wait, why would you half?


in 8i) you found 2/(2r+1)(2r+3)
in 8ii) you are asked to use method of differences for 1/(2r+1)(2r+3) which is half of part i)

Hope this helps
Original post by Kyrus
For question 8 part ii if you did everything correct and just forgot to halve how many marks do you think you would lose


Just 1 mark I expect.
Reply 31
Avatar for S.G.
S.G.
22
Original post by Mr M
You were summing half of the expression you derived in i).


Damn it I didn't half
Original post by SGHD26716
Damn it I didn't half


I expect about half of the candidates will be in the same position. Don't worry about it.
8ii) how many marks would you lose if your answer was 1/6 - 1/(4n+6) and how many marks would you get in 8iii) because i must have carried on the error

many thanks for your help
Reply 34
Avatar for S.G.
S.G.
22
At this rate I've got around 63 marks
Original post by anon326589
8ii) how many marks would you lose if your answer was 1/6 - 1/(4n+6) and how many marks would you get in 8iii) because i must have carried on the error

many thanks for your help


Drop 1 mark in ii) and another in iii). Both parts asked for a single fraction.
Reply 36
Avatar for TeeEm
TeeEm
19
Hard paper for OCR?
Original post by Mr M
Drop 1 mark in ii) and another in iii). Both parts asked for a single fraction.


thanks
Original post by TeeEm
Hard paper for OCR?


No - normal difficulty.
Reply 39
Avatar for 0704
0704
1
How many marks do you think I will lose if I put root 3 +3i for question 2i and therefore got an incorrect answer for part ii as I rationalised the wrong thing?

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