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Reply 200

mathsisjust

Original post by NoahMal

@iMacJack Feelin a tad bit more confident now @kingaaran

What did you get for Q7 for the value of a?

Reply 201

mathsisjust

Original post by edothero

If that's a solid 64/75 then I would like to think you've got an A in the bag, though we can't be sure untill the grade boundaries come out.
Good job nevertheless

What did you get for Q7 for the value of a?

Reply 202

mathsisjust

Original post by Louisb19

Nice. 100UMS if they will allow me to say that the lines are in the same direction instead of that they are parallel. Also I didn't prove it as I thought it was obvious from the graph.

What did you get for Q7 for the value of a?

Reply 203

mathsisjust

Original post by edothero

Chin up mate it ain't over yet. The A-Level consists of 6 modules, all of equal weight.
Best of luck, if you need help PM me :yy:

What did you get for Q7 for the value of a?

Reply 204

username738914

Original post by mathsisjust

What did you get for Q7 for the value of a?

I swear it's in the solutions..

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Reply 205

NoahMal

Original post by mathsisjust

What did you get for Q7 for the value of a?

-1 Because it has to be "real" Therefore the imaginary party had to be equal to zero Hence finding that 4a+4 = 0 therefore a=-4/4

Reply 206

mathsisjust

Original post by Princepieman

I swear it's in the solutions..

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Just clarifying a=-1 is the correct answer right?

Reply 207

mathsisjust

Original post by magicrazzaq

75/75 for me then... As usual

What did you get for Q7 for the value of a?

Reply 208

username738914

Original post by mathsisjust

Just clarifying a=-1 is the correct answer right?

Ofc lol

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Reply 209

mathsisjust

Original post by NoahMal

-1 Because it has to be "real" Therefore the imaginary party had to be equal to zero Hence finding that 4a+4 = 0 therefore a=-4/4

A lot of people got different answers for that Q. :s-smilie:

Reply 210

TH3-FL45H

Does it matter that I didn't do this step in the first proof by induction:

Reply 211

mathsisjust

Original post by NoahMal

-1 Because it has to be "real" Therefore the imaginary party had to be equal to zero Hence finding that 4a+4 = 0 therefore a=-4/4

Is Arsey a math's teacher??

Reply 212

edothero

Original post by mathsisjust

What did you get for Q7 for the value of a?

I did my FP1 last year, for the answers check Arsey's first post, its legit.

Reply 213

mathsisjust

Original post by edothero

I did my FP1 last year, for the answers check Arsey's first post, its legit.

Is Arsey a student or?

Reply 214

mathsisjust

Original post by edothero

I did my FP1 last year, for the answers check Arsey's first post, its legit.

Thanks tho, appreciated :smile:

what did you get for fp1 last yr?

Reply 215

iMacJack

Arsey what Mark would I get if I got the value of A wrong but then I got the corresponding parts right for my value of a? So like I got the mod and arg right for it and the argand right for my value and the last part of the geometrical thing wrong

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Reply 216

GarlicBread01

Original post by Louisb19

Nice. 100UMS if they will allow me to say that the lines are in the same direction instead of that they are parallel. Also I didn't prove it as I thought it was obvious from the graph.

Same, I said they were parallel as I could tell that the gradients were the same but I didnt write down me working out the gradients. Plus the question said to "describe" so I didnt think it was necessary

Reply 217

mathsisjust

Original post by iMacJack

Is Arsey definitely right for that Q for the value of a ??

Reply 218

igotohaggerston

I just want to clarify, do you drop a mark if you say the segments are parallel and show that they are parallel but not one is twice the length of the other. Thats the only thing stopping me from getting full marks looooooooooooooooooool.

Reply 219

oinkk

Original post by TH3-FL45H

Does it matter that I didn't do this step in the first proof by induction:

To me, if you missed out that step, it would make your proof seem counterintuitive. You would've went from having two fractions which could be added, to taking them away.

With that step included, it would've made your intentions very clear.

It could go either way. Considering it was only worth 5 marks, it would suggest to me that this year's proofs are low on the method marks for the inductive step. This means you could get away with it, given the rest of your proof is correct.

But equally, they may have stopped awarding a mark for one of the previous steps in proof questions.

In summary, nobody will be able to tell you. The exam is over with and you will only find out when the mark schemes are released this Summer.