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Would I get a mark for calculating the midpoint for the last one, and putting the y bit equal to 0 and getting p?
I didnt see the simplification for finding the x value in 9)b) and just made my equation equal to the value given. I then used the x value given to find the y value. Would this still give me a mark?
(edited 7 years ago)
Original post by Arsey
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits


how do I know your solutions are correct?
Original post by mathsisjust
how do I know your solutions are correct?


It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now
Original post by 1 8 13 20 42
It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now


I didn't know he was experienced
Original post by Arsey
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits


IAL FP1 solutions here


http://www.thestudentroom.co.uk/showthread.php?t=4106739&p=65033993#post65033993
Original post by Arsey
Here are my solutions to the FP1 paper.

Reasonable paper I thought, a few tricky bits


would you be able to predict grade boundaries for this paper? :tongue:
Original post by mathsisjust
Is Arsey a math's teacher??


Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.
Original post by mathsnerd27
would you be able to predict grade boundaries for this paper? :tongue:


My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)
Original post by NoahMal
My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)


nah

100 UMS - 75
90 UMS - 70
80 UMS - 62
70 UMS - 56
Original post by marinara pizza
nah

100 UMS - 75
90 UMS - 70
80 UMS - 62
70 UMS - 56


The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries
Original post by NoahMal
Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.


lool
Original post by olmomiau
The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries


if you insist:

100 UMS = 75
90 UMS = 70
80 UMS = 65
Original post by NoahMal
My Predictions:

74- 100 UMS
68 - 90 UMS (A* equiv)
60 - 80 Ums (A)
54 - 70 UMS (B)


I second this
do u need to put sqrt 5 in 3 sf to get the one mark?????
Reply 295
I have posted solutions to the F1 paper, I thought it was a fair bit easier than UK FP1
Reply 296
Original post by mathsisjust
how do I know your solutions are correct?


I am Arsey
Reply 297
Original post by mathsnerd27
would you be able to predict grade boundaries for this paper? :tongue:


75 = 100ums
69 = 91ums
68 = 89ums
62 for 80ums
54 for 70ums

would be my guess
Original post by Arsey
75 = 100ums
69 = 91ums
68 = 89ums
62 for 80ums
54 for 70ums

would be my guess


For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?
Original post by 4nonymous
For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?


Usually 1 mark for proving true for n=1, 1 mark for assuming n=k. Sometimes they give a mark for an attempt to prove, sometimes they only give 3rd mark for successful n=k+1 proof. Other 2 marks are available for successful proof for n=k+1 AND conclusion, you will (most definitely) not get conclusion marks without proving for n=k+1.

I'd say you probably have 2 or 3 marks out of 5.

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