idk previous ms allowed like 5 different stuff for factors affecting drag for some other papers. i put down top 2 which came into my head ahah
I put surface area of downwards face of the parachutist, and air density instead of weight, due to some odd way in which the question was worded of something
I put surface area of downwards face of the parachutist, and air density instead of weight, due to some odd way in which the question was worded of something
I put velocity and air density/temperature for the parachuter question
yes, you find the thickness of the aluminium, then multiply by the given width to find the cross section area (assuming a rectangle like area).
Did you say that the area had to be re-calculated after every weight addition? I didn't in the end but I guess the aluminium stretches with added weight
Did you say that the area had to be re-calculated after every weight addition? I didn't in the end but I guess the aluminium stretches with added weight
Extension would decrease as the force increased and young modulus is constant so strain must be less because stress Is higher and young modulus must stay the same so as strain is less extension must be less
Extension would decrease as the force increased and young modulus is constant so strain must be less because stress Is higher and young modulus must stay the same so as strain is less extension must be less
Force increase, so stress increased, so as Ym = Stress/strain strain needs to be greater, so extension must increase
The extension decreases. Force increases so stress increases so YM increases so strain decreases so extension decreases. Was this right?
was this for the last last last last question? they said the acceleration is upwards, so there would be a reaction force downwards, causing cables to extend.
for the Young's modulus questions. The part where they asked if the guy was wrong for using the breaking point to calculate Young's mod. He was wrong because you have to do it within the linear part right?
bad way of explaining. you just need to say that region where he used is where the elastic limit has been exceeded.
Extension would decrease as the force increased and young modulus is constant so strain must be less because stress Is higher and young modulus must stay the same so as strain is less extension must be less
What question is this for?
And wouldn't it be the opposite, as force is proportional to extension?