Man ... Last year the answer to question one for labeling axis when gradient is equal to K was force and Length not extension ... Wtf so i thought its gonna br force per unit length rather than extension !
Man ... Last year the answer to question one for labeling axis when gradient is equal to K was force and Length not extension ... Wtf so i thought its gonna br force per unit length rather than extension !
It's because on that graph, they tried to catch people out. That gradient was still extension.
I did exactly the same I times the area by 4 to account for 4 wires but then I stupidly divided by 4 at the end so I got 1/4 of the answer. Hopefully it will only be 1 mark lost
That's exactly what I done, I thought it made sense in my head but thinking about it now it's so annoying as I know that them marks could cost me
Man ... Last year the answer to question one for labeling axis when gradient is equal to K was force and Length not extension ... Wtf so i thought its gonna br force per unit length rather than extension !
That's because the graph didn't start at the origin. The graph started at the point of extension so the axis was length on that graph (the part before the line was the original length). If the graph starts at the origin then the axis is extension.
I f*cking ran out of time again..... Probably got 42/60, I just need a B for this paper
Same here but I dont just need B on this lol, need to make it up in the next one which meand I can only afford to lose 30 marks, which is not bad. Why do you just need B?
Same here but I dont just need B on this lol, need to make it up in the next one which meand I can only afford to lose 30 marks, which is not bad. Why do you just need B?
EWP is a nice paper for UMS. You can like 95% from dropping 30 marks
For the graph drawing question I did a line linearly decreasing and meeting the axis at the time when the acceleration was 0.
Was this correct?
No because when the resultant force was in terminal velocity it was a parallel line to the axis. The line was a reflection to the line on the graph above