was the power mcq change in rate of word done. q2 w=FP uncertainty= 6.5 angle of rafraction 49 degs something u/2
the mcqs are bothering me alot. help
I think for the refraction it was 15 degrees because it was 80 degrees the other side of the line; so it would be 10 degrees to the normal; therefore 1.5sin10=sintheta ===>theta=sin^-1(1.5sin10)=15.09
Question-The one about the addition of velocities and masses; was the difference that one was scalar and the other was a vector so for velocity you have to also calculate the direction of the physical quantity; whilst with mass you just find the magnitude.
Well i got that wrong then i was talking about Pythagoras god knows why
I chose B because; and I don't think I'm correct, but if the velocity is 0 then displacement=0. So Idk, I thought it would be B, because the negative velocity implies that the ball has gone up past the original height it was released from. I'm not sure though, I thought maybe it wanted to distinguish between speed and velocity?
I put root2(u) since your answer would give a larger answer wouldnt it? Where as root2 multiplied by u will be smaller??
No because root 2 is larger than 1 so it dividing by root 2 makes your value smaller, so it must be u/(root 2) because that squared is u^2 / 2 which halves the energy
I think for the refraction it was 15 degrees because it was 80 degrees the other side of the line; so it would be 10 degrees to the normal; therefore 1.5sin10=sintheta ===>theta=sin^-1(1.5sin10)=15.09
it was from glass to air, a more dense to a less dense medium. when a transverse wave moves from a less to more dense medium it speeds up, which means it moves away from the normal. so i thought 49 degs looked nice.
it was from glass to air, a more dense to a less dense medium. when a transverse wave moves from a less to more dense medium it speeds up, which means it moves away from the normal. so i thought 49 degs looked nice.
It did move away from the normal, the angle in the glass was 10° (90°-80°)