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Physics P1 AQA

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E (J) = m (kg) × c (J/kg) × θ (degrees c)

efficiency (J) = useful energy out / total energy in (× 100%)

efficiency (J)= useful power outtotal power in (× 100%)

E (J) = P(W) × t (s)

v (m/s) = f(Hz) × λ(m)

Payback time = cost of installation / saving per year (£)

kwH = kw x hour

cost (£) = kwh x price per unit (P)
Original post by z_o_e


Yep, I think that looks OK.
Reply 22
Avatar for CaptErin
CaptErin
OP
5
Original post by LNDNWASPS
x


Original post by PrinceKian
x


Original post by TheOtherSide.
x


Original post by _Xenon_
x


Original post by glassriver
x


Thanks everyone for the advice :smile:
I've got that we need to know payback time and the kilowatt hours equation :smile:
Reply 23
Avatar for z_o_e
z_o_e
11
What could I say for the second bit?
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1464118942743.jpg44.4KB
Original post by z_o_e
What could I say for the second bit?
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It dissipates into surroundings.
Reply 25
Avatar for Dave<
Dave<
Thanks that was a big help
Reply 26
Avatar for z_o_e
z_o_e
11
Original post by TheOtherSide.
It dissipates into surroundings.


Thank you xx :yy:

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Hi the main thread can be found here
http://www.thestudentroom.co.uk/showthread.php?t=4111921&page=1

Best of luck for tomorrow! :biggrin:

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