There are 3 matches, each result are independent of each other.
If there were one of each outcome in the 3 matches, there would only be one possible combination of the 3 results. (1 Win, 1 Draw, 1 Lose) - 3 types of outcomes.
The other outcomes are a combination of exactly two types of outcomes (what we are trying to find) and only 1 type of outcome (WWW, or DDD, or LLL). This possibility is the sum of (0.5^3), (0.3^3), and (0.2^3). This is calculated in part ii.
Therefore the probability of exactly two types of outcomes of the 3 outcomes in 3 matches is every single possibility minus 3 types of outcomes, minus only 1 type of outcome.)
P(2types of outcomes) = 1- ((0.5^3)+(0.3^3)+(0.2^3)) - (0.5*0.3*0.2). You may still get 1ECF mark if you got ii wrong.
There are 3 matches, each result are independent of each other.
If there were one of each outcome in the 3 matches, there would only be one possible combination of the 3 results. (1 Win, 1 Draw, 1 Lose) - 3 types of outcomes.
The other outcomes are a combination of exactly two types of outcomes (what we are trying to find) and only 1 type of outcome (WWW, or DDD, or LLL). This possibility is the sum of (0.5^3), (0.3^3), and (0.2^3). This is calculated in part ii.
Therefore the probability of exactly two types of outcomes of the 3 outcomes in 3 matches is every single possibility minus 3 types of outcomes, minus only 1 type of outcome.)
P(2types of outcomes) = 1- ((0.5^3)+(0.3^3)+(0.2^3)) - (0.5*0.3*0.2). You may still get 1ECF mark if you got ii wrong.
The final bracket should be multiplied by 3! as there is different combinations within those 3.
So pissed at myself for these exams. Running out of time and dropping easy marks.
Had less than a minute to do the last question and so use P=2 instead of P<=2. Realised as soon as he said time. Also skipped drawing the histogram cause the scales were just stressful.
You're supposed to use P(X=2). edit: or not? hmmnn well ****
i was hoping they'd be quite low like around 53/72 for an a.
Maybe not THAT low, they haven't been that low for S1 since 2007. I reckon it's likely that an A will be around 55/56 as there were some challenging questions this year.
same most people did but i think the answer is 4 because you had to find the mid of 27.7 and 27.9 instead of just 27.7 for the LQ. and for UQ mid of 31.6 and 32 instead of just 31.6
What did you have to put for the comment on part of 6v?
Well, the women's percentage is higher than mens, but I though in my head, I was uncertain as the sample sizes are different, but I wrote there are more types of shoes for mens than womens.
you would get marks for stating values above Q3+1.5IQR and below Q1-1.5IQR are outliers. probably one. one more for explaining tops. you'd lose the subbing in marks and final answer marks (i think it was a 4 marker)
Seen this question before on past papers, if you correctly multiplied your version of the IQR and then stated that the outliers are 1.5IQR away from the quartiles (giving the boundaries) and stated whether there were any outliers based on your IQR then you get all 4 marks but lose 2 from the previous question for an incorrect IQR. They are very lenient on these questions.
Well, the women's percentage is higher than mens, but I though in my head, I was uncertain as the sample sizes are different, but I wrote there are more types of shoes for mens than womens.
The Women's percentage was definitely lower than the mens, 15.7<20.2