The Student Room Group

Edexcel GCSE maths, give each other questions to do.

Scroll to see replies

Original post by adz95
HOW.PNG

...how?
B and D, because x^2+4x+2x-x^2=6x, as 2x+4x=6x and x^2+-x^2=0
Original post by Ano123
Any takers?
Please explain this answer.:s-smilie:
Reply 162
Original post by Ano123
Do you not understand how to do it?


nope, i'm doing foundation math, desperately need a C grade but can barely understand half of the questions in the past papers.
Original post by chrlhyms
mine wasn't but my maths teacher gave me it as an A* prediction booklet for this year


hi which prediction booklet is this?
Original post by stressedoutt
hi which prediction booklet is this?


im not sure! sorry my teacher just gave it to me
Any predictions??


Posted from TSR Mobile
Original post by hamza772000
Please explain this answer.:s-smilie:


(23)x1=((23)2)x+2 \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left ( \left (\frac{2}{3} \right )^{-2} \right )^{x+2}
So
(23)x1=(23)2x4 \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left (\frac{2}{3} \right )^{-2x-4}
Original post by chrlhyms
im not sure! sorry my teacher just gave it to me


Okay np! ahah its okay
Original post by Ano123
(23)x1=((23)2)x+2 \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left ( \left (\frac{2}{3} \right )^{-2} \right )^{x+2}
So
(23)x1=(23)2x4 \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left (\frac{2}{3} \right )^{-2x-4}
Ahh, now I understand, X=-1. Thanks a lot for your explanation.:smile:
BTW, sorry for the late reply.
Original post by ihatehannah
Make them juicy because this year they have made gcse maths much harder, i'll start us off,http://prntscr.com/b6fzjk


Thats got to be a level
Original post by ihatehannah
x= -1?
how did you work this out?
Maths.png
Am I looking at this wrong or should the values I've circled be '4.505' and '4.495'??
Original post by Tasha_140
Maths.png
Am I looking at this wrong or should the values I've circled be '4.505' and '4.495'??


No the values are right I'm pretty sure :smile:
http://www.mathsgenie.co.uk/resources/june2016p1ans.pdf
here's a predicted paper for tomorrow
Original post by hafsa473
No the values are right I'm pretty sure :smile:



But isn't the upper bound of 4.50 correct to 2d.p 4.505? And the lower bound should be 4.495?
Original post by Tasha_140
But isn't the upper bound of 4.50 correct to 2d.p 4.505? And the lower bound should be 4.495?


Oh wait maybe yeah
sorry bout that it would be 4.505 and 4.495
Original post by ihatehannah
Make them juicy because this year they have made gcse maths much harder, i'll start us off,http://prntscr.com/b6fzjk


not sure if this is correct:

http://imgur.com/KtqUF3s

only in year 11


<DAC=23 <\text{DAC} = 23^{\circ} so as the angle at the centre is double the angle at the circumference this means that <COD=46 <\text{COD} = 46^{\circ} .
<PBC=100<ABC=80 <\text{PBC} = 100^{\circ} \Rightarrow <\text{ABC} = 80^{\circ} .
<ADC=100 <\text{ADC} = 100^{\circ} since ABCD is a quadrilateral with all vertices on the circumference of the circle and ABC is opposite angle to ADC.
If anyone wants me to go on I can I have the full solution but it takes ages to write here.
(edited 7 years ago)
Original post by haarithiop
not sure if this is correct:

http://imgur.com/KtqUF3s

only in year 11


It's a year 11 question.

Quick Reply

Latest