AQA A Level Maths Core 2 - 25th May 2016 [Exam Discussion]

For 4)c) I believe it was just the sum formula by using n=18 (21-4+1) and since you know the first value "a" and the difference "d" you can just plug it into the formula
S18=18/2 times 2a...? Could be wrong but going with it

10 for effort don't put urself down!!

I'm sorry for my generic reply but it really does depend on what you worked out and did or did not do.

For that specific 6 mark questions I expect the marks to be divided into:

M4
B1
A1

Thereby divided into:

½r^2θ = ½absinC – ½r^2θ → r^2(θ) = ½absinC –M1

r= √(½absinC/θ) → {No loss of accuracy i.e. no participation in premature rounding} – M1

Note μ , δ and σ represent a candidate's answer
9 – r = μ
8 – r = δ

For the above B1

rθ = σ – M1

Perimeter = μ + δ + σ + 5 – M1

Perimeter to 3 significant figures – A1

That's how I believe the marks will be split, of course they are my interpretation of the distribution of marks [Which I'm pretty confident about but of course not entirely sure]

You can judge from above how many marks you may have gained/lost. But please, please, please take it with a pinch of salt.

You have one more Maths exam left and you should not let yourself be downhearted about what may have happened today. Continue to revise, smash that applied module and results day may not be as bad as you may think. Good luck!

I feel you

I'm sorry for my generic reply but it really does depend on what you worked out and did or did not do.

For that specific 6 mark questions I expect the marks to be divided into:

M4
B1
A1

Thereby divided into:

½r^2θ = ½absinC – ½r^2θ → r^2(θ) = ½absinC –M1

r= √(½absinC/θ) → {No loss of accuracy i.e. no participation in premature rounding} – M1

Note μ , δ and σ represent a candidate's answer
9 – r = μ
8 – r = δ

For the above B1

rθ = σ – M1

Perimeter = μ + δ + σ + 5 – M1

Perimeter to 3 significant figures – A1

That's how I believe the marks will be split, of course they are my interpretation of the distribution of marks [Which I'm pretty confident about but of course not entirely sure]

You can judge from above how many marks you may have gained/lost. But please, please, please take it with a pinch of salt.

You have one more Maths exam left and you should not let yourself be downhearted about what may have happened today. Continue to revise, smash that applied module and results day may not be as bad as you may think. Good luck!

Yep, I got the same as you did.
But they said the transformation was 3√x^2 + 1 not 3√x^2 + 9 which totally confused me.

I remember when I looked at the question it was 3√x^2 + 9, right??

I just really didn't know whether I read the question wrong or not.

For 4)c) I believe it was just the sum formula by using n=18 (21-4+1) and since you know the first value "a" and the difference "d" you can just plug it into the formula
S18=18/2 times 2a...? Could be wrong but going with it

Thank you so much for your help!

Thanks man, have to give a big push for M1 now.. Also

I rounded the radius, so i got 5.83, so the answer i got was 16.2? would i get the marks? also i forgot to show my working out for 8 - radius, did it in my head?

Your answer of 16.2 is a fair bit beyond the 13.8 so it wouldn't get the A1 mark

Unfortunately I believe that the B1 mark comes from both the (9 – r) and (8 - r) where you have to show them being worked out so I don't think you would've gotten it

But of course this isn't the real mark scheme so you never know!

Yup big push for M1 and you'll be fine. It isn't the easiest module but once you've got the hang of it that's all there is to it

Your answer of 16.2 is a fair bit beyond the 13.8 so it wouldn't get the A1 mark

Unfortunately I believe that the B1 mark comes from both the (9 – r) and (8 - r) where you have to show them being worked out so I don't think you would've gotten it

But of course this isn't the real mark scheme so you never know!

Yup big push for M1 and you'll be fine. It isn't the easiest module but once you've got the hang of it that's all there is to it

Your answer of 16.2 is a fair bit beyond the 13.8 so it wouldn't get the A1 mark

Unfortunately I believe that the B1 mark comes from both the (9 – r) and (8 - r) where you have to show them being worked out so I don't think you would've gotten it

But of course this isn't the real mark scheme so you never know!

Yup big push for M1 and you'll be fine. It isn't the easiest module but once you've got the hang of it that's all there is to it

no sorry not 16.2 i got 13.2? any idea now? and yeah hopefully ill do ok in it

A1 marks are rewarded for the exact answers so even an answer of 13.7 or 13.9 (When the actual answer is 13.8) would unfortunately not score the mark

In terms of ums if you had 70/75 as an example and 100 ums was 73, 90 was 68 would your ums be 90 (based on grade boundaries) or is it based on your mark?

NOTE: I made up these numbers as an example.

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Huh? No, it would be somewhere between 90 and 100 (likely mid 90s)

Did anyone else do the exponential graph the wrong way round?? I rushed and drew it as if it were a normal exponential graph e.g. y=2^x. But apparently it was like that but reflected in the Y axis... Oh well, I should still get the mark for labelling the correct intercept as that shouldn't have changed.

i left the normal equation in the form y-y1 = m(x-x1)

how many marks willl i lose

How was the expansion question done , when expanded I got x^10 to be like -18144 !