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2016 May 25th Edexcel Core 2 Questions and answers. [Unofficial mark scheme] 2016

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Grade boundary ideas?
Original post by X_IDE_sidf
http://www.thestudentroom.co.uk/atta...1&d=1464204940 <-- NEW PDF. This is V2 and has been layed out in a more stylish manner and has Q 9c corrected

Edit: to satisfy my ocd, the real scanned paper will be hitting shelves soon.


Link doesn't work :-(
Original post by HannahC-H
Link doesn't work :-(


http://docdro.id/xPyA5Yl

edit: DERP, forgot to change Q 8. =0 not -1
(edited 7 years ago)
For question 7 would you lose a mark for not putting +c on the integral?
Original post by X_IDE_sidf


TY
Original post by bulletman54
For question 7 would you lose a mark for not putting +c on the integral?


I think so, the question didn't specify limits in (a) so without + c you are technically incorrect.
Original post by X_IDE_sidf
I think so, the question didn't specify limits in (a) so without + c you are technically incorrect.

What was the exact wording of the question ?
Original post by bulletman54
What was the exact wording of the question ?


find ∫(3x−x32)dx\int (3x-x^{\frac{3}{2}})dx
If I got x = ~17 and didn't sub back into P, how many marks do you reckon I'll lose?
Original post by bulletman54
What was the exact wording of the question ?


Usually the mark scheme says (+c) in brackets as in previous years, so I don't think you'd lose a mark
Original post by bulletman54
For question 7 would you lose a mark for not putting +c on the integral?


In previous years its in brackets and not required
Original post by medapplicant2016
If I got x = ~17 and didn't sub back into P, how many marks do you reckon I'll lose?

2 i think cause u made a rounding error and never subbed for the min value
Original post by medapplicant2016
In previous years its in brackets and not required

Could you link me the markscheme for a question like this from a previous year?
Original post by medapplicant2016
In previous years its in brackets and not required


source
Original post by X_IDE_sidf
http://docdro.id/xPyA5Yl

edit: DERP, forgot to change Q 8. =0 not -1


Wasn't 6i

1−2cos(θ−π5)1-2cos(\theta -\frac{\pi}{5})

and not

1−2sin(θ−π5)1-2sin(\theta -\frac{\pi}{5})
For the perimeter question, if I substituted x=17, how many marks can I expect to lose ?
Original post by UKoE Luna
Wasn't 6i

1−2cos(θ−π5)1-2cos(\theta -\frac{\pi}{5})

and not

1−2sin(θ−π5)1-2sin(\theta -\frac{\pi}{5})


we are on to V4 now http://docdro.id/18BTG2C

Thanks
Original post by X_IDE_sidf

6 1−2sin⁡(θ−π5)=01-2\sin(\theta - \frac{\pi}{5})=0 solve for θ\theta and 4cos⁡2x+7sin⁡x−2=04\cos^2 x + 7\sin x - 2 = 0

6 i) (3 marks) 8π15\frac{8\pi}{15}or −2π15\frac{-2\pi}{15}
ii) (6 marks)
Unparseable latex formula:

345.5$^{\circ}$

or
Unparseable latex formula:

194.5$^{\circ}$




Is question 6 written out correctly? I get 11π30\frac{11\pi}{30}or 31π30\frac{31\pi}{30}

EDIT: Seen that there have been amendments since then. Shouldn't 8i) be a−59\frac{a-5}{9}?
(edited 7 years ago)
Original post by X_IDE_sidf
source


Original post by bulletman54
Could you link me the markscheme for a question like this from a previous year?


http://qualifications.pearson.com/content/dam/pdf/A-Level/Mathematics/2013/Exam-materials/6664_01_msc_20150812.pdf

See question 6
Original post by bulletman54
2 i think cause u made a rounding error and never subbed for the min value


That's what I thought, I did get 16.something though, and did work out f"(x) > 0, which usually gives you 2 marks (you don't need to sub)

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