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Edexcel AS Mathematics C2- 25th May 2016 Thread

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Yeah I think so. 2^2x+5 is the same as
2^2x 2^5. So you get 32y^2 -7y=0 I think which let to x = -2.19
Original post by b0bzzta
could someone go through the log question for me? it was log3(3b+1)-log3(a-2)=-1


log3(3b + 1/a - 2) = - 1
3^-1 = (3b + 1)/(a - 2)
(3b + 1)/(a - 2) = 1/3
3b + 1 = 1/3(a - 2)
3b + 1 = a/3 - 2/3
3b = a/3 - 5/3
b = (a - 5)/9

That's what I did :smile:
Think that's equal to what I got
Original post by Steliata
log3(3b + 1/a - 2) = - 1
3^-1 = (3b + 1)/(a - 2)
(3b + 1)/(a - 2) = 1/3
3b + 1 = 1/3(a - 2)
3b + 1 = a/3 - 2/3
3b = a/3 - 5/3
b = (a - 5)/9

That's what I did :smile:


Wow same, thank you I was stressing :smile:
Hey can anybody go through the trig identities question, it was 1-2cos(theta-PI/5) = 0 then ii) was 4cos^2x + 7sinx-2=0 i think for 0<=x<=360
Original post by SaadKaleem
Looks like you did a terrible job, at making the Mark scheme official.

Page 2:

Spoiler



Looks like edexcel have still got to update their template and include examiner comments like they normally do once the results are in and make small adjustments where necessary
Reply 567
Original post by neil20143
I'm in the same boat as you. I think I'll just convince my teachers that I can get an A* next year because they originally thought I would. It depends what you got on C1 and C2 but Stats generally is either a love it or hate it paper. I'd say really concentrate and normal
distribution and probability.
Vvs1 usually has a bunch of small questions which are linked together so you have to be extra careful because you won't be given follow through marks so if the first part is wrong then the second 3rd so on are most probably wrong too.
Reply 568
[QUOTE=b0bzztatmp_22381-Screenshot_2016-05-26-02-47-15-543741191.png;65177959]Hey can anybody go through the trig identities question, it was 1-2cos(theta-PI/5) = 0 then ii) was 4cos^2x + 7sinx-2=0 i think for 0<=x<=360 your welcome lol.
Reply 569
tmp_22381-Screenshot_2016-05-26-02-47-15-1099573578.png
Original post by jbaten
your welcome lol.
This video really sums up the C2 exam...

(edited 7 years ago)
Reply 571
tmp_14311-Screenshot_2016-05-26-02-47-151047104247.png
Original post by jbaten
tmp_14311-Screenshot_2016-05-26-02-47-151047104247.png



How did you get this?
Original post by JackNiblett
I got something like 28/6 and got like 4000 and something?? It still worked though, so what does this mean?


I don't even know anymore, that question ****ed me over. Its only 4 marks though so it shouldn't be that big of a deal
Did anyone else get P is 66? How are people getting 120?
how did people find the upper bound needed to find the area of s ?
Original post by discuss
how did people find the upper bound needed to find the area of s ?


The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x

Original post by Darkseid1234
Did anyone else get P is 66? How are people getting 120?


When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120
Original post by Bhaiyattt
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x



When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120


I defo did that and got 66 and people I spoke to got similar answers as well.
I can't remember the exact equation for P feel free to remind me but i'm sure it was 66
Actually the equation for P was 1000/X+X/12(4pi+36-3root3)
Original post by Bhaiyattt
The curve touched the X axis at two points. One of them was 0 and the other one, to find out what it was you needed to sub in y = 0 into the equation which would give you a value for x



When you differentiated the equation, and made it equal to 0, you get an answer of X = 16.63. If you sub that value of X back into the equation for P, you get an answer of P = 120


I substituted X into a formula do you reckon i'll get a method for substituting even though it may have been the wrong formula?

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