Edexcel Physics IGCSE 1P Unofficial Mark Scheme 25th May 2016

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81.6%, you might get an A or an A* depending on what the boundary is set at. Over the last few years it's averaged around 82% so you might be lucky!

82%??? crap

Reply 61

igggy

Original post by cornflakeexpert

82%??? crap

no its hasnt it was 76 last year and that paper was so mucheasier than ours . It will be low 70s

Reply 62

Kloppo

Man, that exam was a disaster. Whats with the bear thing ffs ??

Reply 63

akaash13

Original post by conradliebers

2.h)
Orbital Speed = 17123.28767km/hr (3)

Thank you for putting this mark scheme online. Really appreciate it. One thing though; I am pretty sure that it said that 150,000,000km was the radius, not the circumference.

So wouldn't it be
150,000,000 * 2 * pi = 94247796.1km
365 * 24 = 8760

so divide the first by the second to get 107588.7895km/h
roughly equal to 108000km/h

Reply 64

conradliebers

Original post by akaash13

Yes I think that was right yes, I remember it now. It was because a friend told me that and I got confused.

Reply 65

aaljhfgahsj

Original post by akaash13

I got that as well, can you answer my other question on the other page?

Reply 66

akaash13

Original post by aaljhfgahsj

Guys for the question about the speed of the train I got 8.48... So 8.5(3sf) but a lot of people are saying its 12... Which it could be, but correct me if I am wrong but the question wanted the velocity of the train..so v=square root of ke/halfxmass, and I'm pretty sure the ke was given in MJ (so times by 1mil), and when you do that it gives you my answer...so which one is correct, and if it is 12 can someone plz explain?

Hi again,

This is how I got 12.

I believe it was something like 1.8MJ, which you divide by one half (i.e. Multiply by two) to get 3.6MJ because the equation is 1/2 times m times velocity squared. This gives mass times velocity squared. Then divide by mass which was 25000 kg I think to get 144 and square root to get 12. I think that you forgot to multiply by 2 because I di the calculation without multiplying by 2 and I got what you got.

Reply 67

aaljhfgahsj

Original post by akaash13

Ok thanks...hopefully grade boundaries will be lower this year haha

Reply 68

Olijones100

Original post by JKram

81.6%, you might get an A or an A* depending on what the boundary is set at. Over the last few years it's averaged around 82% so you might be lucky!

Sorry to point out but this is a ludicrous statement. Grade boundary has only ever crept to 142/180 once and only ever been over 140 once. For those interested the % of 142/180 is 79%, far too high for the paper. In recent years the grade boundary has hovered around 132-136 for the a*, however in more difficult years it has dropped to mid to high 120's.

Also, I believe 3a) was around 142 or 3 kPa can't remember now, don't think it was in the thousands

(edited 7 years ago)

Reply 69

Pink_Sparkles

Original post by Job738338

and we have maths tommorow :bawling:

yup!!!!!

Reply 70

ursulab

Does anyone have a drawing of what the TIR into the jewl is supposed to look like?

Reply 71

willp12345

2b) thermal not kinetic

Reply 72

qazwaz

I hope g boundaries are low but grade boundary has been above 142/180 Olijones100, for jan 2016 it was 145/180
also i'm pretty sure the measurement between 2 dots was 5.4 not 5.3

Reply 73

pk789

Original post by willp12345

2b) thermal not kinetic

its kinetic

Posted from TSR Mobile

Reply 74

conradliebers

Original post by willp12345

2b) thermal not kinetic

It is kinetic. I've done enough past papers to know.

Reply 75

conradliebers

Original post by qazwaz

I hope g boundaries are low but grade boundary has been above 142/180 Olijones100, for jan 2016 it was 145/180
also i'm pretty sure the measurement between 2 dots was 5.4 not 5.3

It's a rough measurement, the mark scheme will give a range. I wrote 6.3 because the image it gave wasn't exactly perpendicular/straight so it looked a bit like some parallax error.

Reply 76

conradliebers

Original post by Olijones100

You use the formula P1V1 = P2V2

If the first pressure you use is 101kPa and the volume is 1700 litres, you multiply them to get 171700. Because volume 2 was 12 litres, you simply divid 171700 by 12 in order to get the value which is already in kPa which is 14308.3kPa. Agreed?