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C12 IAL May 2016 Edexcel Solutions

Here are my solutions to the C12 IAL may 16

Not bad at all

https://drive.google.com/open?id=0B3xSC6XqSy7kSmV2Ul9uM0hsbXM
(edited 7 years ago)

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Reply 1
Avatar for Zacken
Zacken
22
Props to you for doing that 16 question paper. :tongue:
Seemed like a standard paper. In my opinion, just *slightly* harder compared to January.
Reply 3
Avatar for kprime2
kprime2
OP
20
Original post by Zacken
Props to you for doing that 16 question paper. :tongue:


It's only C1 and C2. Didn't take too long :tongue:
Original post by kprime2
Here are my solutions to the C12 IAL may 16

Not bad at all

https://drive.google.com/open?id=0B3xSC6XqSy7kZVhBRlBtSm5sVGc


How would u compare it to last 2 years C12?
Reply 5
Avatar for kprime2
kprime2
OP
20
Original post by Saad69
How would u compare it to last 2 years C12?


No idea. I didn't write answers for them. How did you find the paper?
Reply 6
Avatar for Ayman!
Ayman!
15
Predicting high boundaries for this one.

Seems like you don't care about the copyright kerfuffle that's going on, huh, mate? 😂
Original post by Ayman!
Predicting high boundaries for this one.

Seems like you don't care about the copyright kerfuffle that's going on, huh, mate? 😂


Please no :laugh:
F*** I see like 30 marks lost I hope boundaries are LOWWWWWWWWWWWW
Reply 9
Avatar for kprime2
kprime2
OP
20
Original post by Ayman!
Predicting high boundaries for this one.

Seems like you don't care about the copyright kerfuffle that's going on, huh, mate? 😂


Couldn't care less. Either way someone somewhere in the world will upload the answers lmao
Reply 10
Avatar for Ayman!
Ayman!
15
Original post by Imperion
Please no :laugh:


Not like it matters for you; 125/125 is still full. :wink:
Original post by Ayman!
Not like it matters for you; 125/125 is still full. :wink:


Why are you bragging though?

Posted from TSR Mobile
Original post by Saad69
F*** I see like 30 marks lost I hope boundaries are LOWWWWWWWWWWWW


I'm afraid that could probably cost you A grade, Will probably be close!

Original post by Saad69
Why are you bragging though?

Posted from TSR Mobile


What do you mean?
Reply 13
Avatar for Ayman!
Ayman!
15
Original post by Saad69
Why are you bragging though?

Posted from TSR Mobile


I'm not; I didn't sit this exam, I'm just pulling Imperion's leg. Apologies if you took it any other way. :smile:
(edited 7 years ago)
Reply 14
Avatar for EUSHA
EUSHA
2
Original post by kprime2
Here are my solutions to the C12 IAL may 16

Not bad at all

https://drive.google.com/open?id=0B3xSC6XqSy7kZVhBRlBtSm5sVGc


can you please explain how you did no.16 c? was the shaded area only above the x axis?
Reply 15
Avatar for kprime2
kprime2
OP
20
Original post by EUSHA
can you please explain how you did no.16 c? was the shaded area only above the x axis?


I think the solution is pretty clear. You subtract the little unshaded area from the triangle. Which bit don't you get? Yes the shaded area is only above the x-axis.
Original post by Ayman!
Not like it matters for you; 125/125 is still full. :wink:

My dreams are valid :mmm:

Original post by Saad69
Why are you bragging though?

Posted from TSR Mobile


Lol he's messing, lax.
Reply 17
Avatar for t
t
13
Original post by kprime2
I think the solution is pretty clear. You subtract the little unshaded area from the triangle. Which bit don't you get? Yes the shaded area is only above the x-axis.


Basically when you subtracted the triangle area from area under curve you forgot that there's a little bit extra under R which also needs to be subtracted (bounded by x axis and above curve). Therefore I calculated the solution to be 27/64.
(edited 7 years ago)
Reply 18
Avatar for kprime2
kprime2
OP
20
Original post by I <3 WORK
Basically when you subtracted the triangle area from area under curve you forgot that there's a little bit extra under R which also needs to be subtracted (bounded by x axis and above curve). Therefore I calculated the solution to be 27/64.

No that bit youre talking about isn't shaded...
Reply 19
Avatar for t
t
13
Original post by kprime2
No that bit youre talking about isn't shaded...



Yes but this is my point lol. When you subtract area under the curve from triangle area you get the shaded area (R) AND the bit under the x axis (above the curve). So in order to get the area that's shaded ONLY you will further have to subtract area under line (under x axis) from area under curve. And this value is subtracted from 11/64.
(edited 7 years ago)

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