Mr M's OCR (not OCR MEI) Core 2 Answers May 2016

Hi, for q6 part iii I went wrong in the method somewhere and got the wrong answer, but I realised and still wrote N=38. How many marks would I get? Also for the equating coefficient question I used k as the coefficient and somehow got +/- root 1/9. Would I get any marks?

For 9 (ii) dont even know what i did but ended up gettin a=0 and when i subbed a into another equation it gave me k=0 would i even get a mark for writing k=0 or will they ignore it?

6iii) should get full marks

your other question just sounds wrong - probably no marks for that bit

7) drop 1

9iii) drop 1 probably

Mr M's OCR (not OCR MEI) Core 2 Answers May 2016


1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)


2. (i) $\displaystyle \frac{3 \pi}{10}$ (2 marks)

(ii) $r=20.4$ (3 marks)


3. (i) $\displaystyle 27 +27kx+9k^2x^2 +k^3x^3$ (4 marks)

(ii) $k=\pm \sqrt{3}$ (2 marks)


4. (i) $\displaystyle \log_3 \frac{x^2}{x+4}$ (2 marks)

(ii) $x = 12$ (4 marks)


5. (a) $\displaystyle \frac{x^4}{2} -x^3 +2x^2-6x+k$ (3 marks)

(b) (i) $\displaystyle \frac{2}{a^2} - \frac{6}{a} + 4$ (4 marks)

(ii) 4 (1 mark)


6. (i) $k=91$ (3 marks)

(ii) $\displaystyle S_{16} = 978$ (2 marks)

(iii) $N=38$ (6 marks)


7. (i) Quotient $x^2-4x+3$ and remainder 0 (3 marks)

(ii) $x=1$ or $x=-1$ or $x=3$ (3 marks)

(iii) Show (2 marks)

(iv) $\displaystyle \frac{512}{15}$ (4 marks)


8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor $\displaystyle \frac{1}{9}$ (2 marks)

(iii) Sketch showing $(0, \frac{1}{9})$ as the only point of intersection (2 marks)

(iv) $x=6.73$ (3 marks)

(v) 9.60 (3 marks)


9. (i) $\displaystyle \frac{2 \pi}{a}$ (1 mark)

(ii) $\displaystyle a=\frac{5}{3}$ and $\displaystyle k=\frac{\sqrt{3}}{2}$ (3 marks)

(iii) $\displaystyle x=\frac{\pi}{3a}$ and $\displaystyle x=\frac{4 \pi}{3a}$ (4 marks)


Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.

Will you be making one for edexcel maths paper 1?

For question 6iii, if I used the right method, used the formula for sum of the arithmetic sequence, calculated sum to infinity plugged in the numbers and made it > than a sum to infinity, but ended up with the wrong value of N, so I went wrong somewhere in my calculations, how many marks would I get?

Sorry I'm still confused about -3 not being a solution to 4 (ii) - why isn't 2log3(-3) = log9?

Mr M I am so sorry for asking this in an a level thread but can you pleaseeeee make a mark scheme for the edexcel mathematics A exam higher that we did today pleaseeee, I really want to get an accurate judgement about how I did today so that I can see how many marks I need to get an A* overall.

Than you soooo much!!

Try putting log(-3) on your calculator, its invalid

thanks for replying - yep I was wondering why it's invalid, and why for 2log3(-3) the power 2 wouldn't 'go up' and square the -3 as it would a positive number?