AQA AS Chemistry unit 1 resit May 27th 2016
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Original post by Danny786
What did you guys put for the one about methanol and methanoil
It was to do with Hydrogen bonding ok sure
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It was to do with Hydrogen bonding ok sure
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Ye methanol has H bond. Other one has VDW
Original post by Danny786
Sorry I mean m3
Pretty sure it's 49.30%
Original post by Bloom77
I got
Chromatography for the seperation question but a lot of people said fractional distillation.
Cu3H2C2O8
0.451g
1065000 for the mass
49.3% (this is deffo right)
And first method because 4 miles of phosphoric acid is produced instead of 2 and also, no second product is produced in the first method. However, you can also say second method because it's a one step reaction.
Chromatography for the seperation question but a lot of people said fractional distillation.
Cu3H2C2O8
0.451g
1065000 for the mass
49.3% (this is deffo right)
And first method because 4 miles of phosphoric acid is produced instead of 2 and also, no second product is produced in the first method. However, you can also say second method because it's a one step reaction.
how did you get 49.3% i got 15 or 16 something
SF4 Bond Angles: 87.5 and 117.5
SF6 Bond Angle: 90, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
SF6 Bond Angle: 90, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
(edited 7 years ago)
Original post by berries366
What did everyobe write for the similarities and differences question. I put that the isoptopes abundance is the same as a similarity but 2+ions are produced as a difference. No idea if thats right 
Same, that was the only nasty question
Original post by Bloom77
Sorry I mean m3
Pretty sure it's 49.30%
Pretty sure it's 49.30%
Yes I also got 49.3 and 0.451m3 but everyone got 0.113 so I think we did it wrong somehow?
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Original post by Hello123Anonym
SF4 Bond Angles: 87.5 and 117.5
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
Could you leave it as Cu3O8C2H2
Original post by Hello123Anonym
SF4 Bond Angles: 87.5 and 117.5
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
you know for the formula bit i got those ratios but i didnt write it out as formula like that just wrote how many of each element
What did you guys get for the similarities and differences?
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
Original post by TJ_gym
was the SF4 square planar
Original post by Bloom77
What did you guys get for the similarities and differences?
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
yeah i wrote that and added so a different m/z ratio
Original post by Bloom77
What did you guys get for the similarities and differences?
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
difference m/z ratio
Original post by vinchy
i Got 49 .3 and 0.113 m3
how did you get 49.3
Original post by Bloom77
What did you guys get for the similarities and differences?
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
I got similarity of That their isotopes
And differences is that it forms +2 ion and not a +1
I guess it's 0.113 and 0.451 is wrong and I got that too
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What did you guys get for Element Y? I got Argon...
Original post by Hello123Anonym
SF4 Bond Angles: 87.5 and 117.5
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
SF6 Bond Angle: 120, Octahedral
Empirical Formula: 2.75g Cu, 0.029g H, 0.348g C, 1.873g O
Ratio: 3 , 2 , 2 , 8
Formula: Cu3(OH)2(CO3)2
SF6 has a bond angle of 90
2nd Balanced Equation: Cu2(OH)2CO3(s) + 4 HCl(aq) = 2 CuCl2(s) + CO2(g) + 3 H2O(l)
Observation: Effervescence (of a colourless gas)
Observation: Effervescence (of a colourless gas)
(edited 7 years ago)
Original post by Studious_Student
What did you guys get for Element Y? I got Argon...
No, it was sulfur
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