AQA AS 2016 - CHEM1 (Resit) Unoffical Mark Scheme

Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,4,4 - trimethylpentane or equivalent
c) C₈H₁₈ + 12.5O₂ ------> 9H₂O + 8CO₂
d) but-1-ene
e) C₁₄H₃₀
f) Isomers question. Chain isomer = H₂C=C(CH₃)₂ Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu₂(OH)₂CO₃ + 4HCl -----> 2CuCl₂ + 3H₂O + CO₂
c) Effervescense
d) Something like Cu₃O₈H₂C₂
e) Shapes question - SF₆ = Octohedral , 90 degrees SF₄ = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) -Element Y is Sulphur. -Large jump in eneries from 6^th to 7^th ionisation enegies -So 7^th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m³ (3 sig figs needed)
b) 1065 Kg or 1.065x10⁶ g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.

I think I agree with all, but 3b will only accept 2,2,4-trimethylpentane, and 4e was a sea saw shape so will accept angles 90,120 and 180

But you can read it backwards? So why not 2,4,4? It's the same thing right?

But you can read it backwards? So why not 2,4,4? It's the same thing right?

No I'm pretty sure you have to write smallest numbers as possible. May say accept 2,4,4

I think you do it so numbers are as low as possible

how do vdW form can someone write an actual ms answer please googles a load of bull

Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,2,4 - trimethylpentane (might accept 2,4,4 - trimethylpentane)
c) C₈H₁₈ + 12.5O₂ ------> 9H₂O + 8CO₂
d) but-1-ene
e) C₁₄H₃₀
f) Isomers question. Chain isomer = H₂C=C(CH₃)₂ Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu₂(OH)₂CO₃ + 4HCl -----> 2CuCl₂ + 3H₂O + CO₂
c) Effervescense
d) Something like Cu₃O₈H₂C₂
e) Shapes question - SF₆ = Octohedral , 90 degrees SF₄ = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) The elements that you could say were Aluminuim because removing electron form 3p shell and Sulfur because of pair repulsion.
d) -Element Y is Sulphur. -Large jump in eneries from 6^th to 7^th ionisation enegies -So 7^th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m³ (3 sig figs needed)
b) 1065 Kg or 1.065x10⁶ g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.

how do vdW form can someone write an actual ms answer please googles a load of bull

Could yoU explain how you got 0.113 instead of 0.451/0.453

Here is my unofficial mark scheme. Anything in bold I am not sure if it's right. So if you have any idea then please tell me so i can add it! If i have missed anything out then aslo let me know!

Section A

1.
a) Relative Atomic mass Definition
b) Magnetic Field
c) - Ions accept electrons -Current is formed which is proportional to abundance
d) Something like 28.065 for the RAM
e) Similarity= Peaks still at original m/z values becuase +1 ions are still formed. Difference - Peaks at half the m/z values becasue high energy electrons will produce +2 ions

2. (Can't rmember what topic this was. I think it was about Van Der Waals)
a) -Electron Density randomly shifts -Creating areas of +ve and -ve charge on molecule - Attraction between molecules which is intermolecular force/VDW
b) O-H bond big electronegative difference allows for hydrogen bonds. Hydrogen bonds are stronger than VDW.
c) The Se molecule is larger? This means the VDW forces are stronger between molecules

3. (Questions about Alkanes?)
a) Group is alkane
b) 2,2,4 - trimethylpentane (might accept 2,4,4 - trimethylpentane)
c) C₈H₁₈ + 12.5O₂ ------> 9H₂O + 8CO₂
d) but-1-ene
e) C₁₄H₃₀
f) Isomers question. Chain isomer = H₂C=C(CH₃)₂ Postion isomer = But-2-ene Functional Isomer = Cyclic Alkane so basically a square skeltal formula

4. (The weird reactions and the shapes question?)
a) Balancing equation I couldn't remember
b) Cu₂(OH)₂CO₃ + 4HCl -----> 2CuCl₂ + 3H₂O + CO₂
c) Effervescense
d) Something like Cu₃O₈H₂C₂
e) Shapes question - SF₆ = Octohedral , 90 degrees SF₄ = I thought it was trigonal bipyramidal with the lone pair in the horzontal plane with angles of 120 degrees and 90 degrees but others saying it was tetrahedral with and of 107 degress

Section B

5. (Period 3 stuff)
a) - Ionisation energies increase -Increasing proton number - Similar Shielding -Attraction between outer electron and nuclues gets stronger -The bigger nuclear charge reduces atomic radius (I don't think this point is needed)
b) -Silicon has highest melting point. -Because of macromolecular/Giant covelant structure. -Strong covelant bonds throughout structure. -Requires high amounts of energy to break.
c) The elements that you could say were Aluminuim because removing electron form 3p shell and Sulfur because of pair repulsion.
d) -Element Y is Sulphur. -Large jump in eneries from 6^th to 7^th ionisation enegies -So 7^th electron in inner shell so sulphur must be the element Y.

6. (Calculations)
a) 0.113m³ (3 sig figs needed)
b) 1065 Kg or 1.065x10⁶ g
c) Percentage yield = 49.3%
d) Method 1 because its 100% atom economy. Only producing one product.

Could yoU explain how you got 0.113 instead of 0.451/0.453

The ration was 1:1 for phsophorus to the oxide. So work out the mol of the phsphorus = 220g/124 = 1.774 mol

Then use pV = nRT to find volume. 500 degress celcius (converted to 773K) and 101kPa

V = (1.774 x 8.31 x 773)/101000 = 0.1128 m³ = 0.113 m³

I put non-polar molecules, have very little difference in electronegativity so VDW forces form between molecules.

Not sure if you would get marks for the skeletal as it asked for displayed formula

Wasn't is P4O10 - for the mr?
You just did 124 for the Mr


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that's what i put my g, i think you have to talk about electron clouds and how at any given time one side is less neg and one side is more neg so attract other electron clouds etc...

thanks man! do you remember how many marks each question was worth?