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Edexcel IAL Chemistry Unit 1 (WCH01 )/ May 27 June 2016

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Original post by omar5478
I got this from wikipedia which shows that the answer is probably D

Link:https://en.m.wikipedia.org/wiki/Catalytic_reforming

image.png


Aw man! :banghead::bawling:
Original post by omar5478
I got this from wikipedia which shows that the answer is probably D

Link:https://en.m.wikipedia.org/wiki/Catalytic_reforming

image.png


wth is this :biggrin: question is about reforming not aromatization etc....
Same here 😍
Guys what was the empirical formal of the hydrocarbon in the Mcq question 😂?
Original post by Hamadtype-
wth is this :biggrin: question is about reforming not aromatization etc....


It is written at the top that these are the four major "catalytic reforming reactions" not aromatization
Original post by Sandy_Vega30
Aw man! :banghead::bawling:


Don't worry though. Unlike most people here, I think the grades would be relatively low (like 63-65)
Original post by Mimiastc
Guys what was the empirical formal of the hydrocarbon in the Mcq question 😂?


I got CH2
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13
image.jpeg

So this is the verdict according to CGP. It says that alkanes are reformed into cycloalkanes and aromatic hydrocarbons. :frown:
what was the answer for the ppm question and the number of atoms in an element (cant remember the exact element)?
Original post by Magdah Omer
I got CH2


But there was a O too it was the one with the percentage abundences 😂
(edited 7 years ago)
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Original post by mr.holmes
what was the answer for the ppm question and the number of atoms in an element (cant remember the exact element)?


For the PPM you had to divide by a million then times by a thousand (can't remember the actual values). The number of atoms in the compound they gave you has to be counted, and multiplied by the mole and again multiplied by Avogadro's constant.
Original post by mr.holmes
what was the answer for the ppm question and the number of atoms in an element (cant remember the exact element)?


ppm - 8x10^-3g

No. of atoms in an element - there were 5 atoms, so 3.0x10^24.
Original post by Mimiastc
But there was a O too it was the one with the percentage abundences 😂


ohhh sorry i was talking about the alkenes one
for that one i think i got c2h40
Im totally failing if grade threshold is 68 or 67😢😢😢
ok so what do you expect the grade boundaries to be (lower than the January sessions)? :s-smilie:
Original post by Sandy_Vega30
It made sense because large compounds like Decane are reformed to cyclohexane and stuff. I got side tracked by that. Smaller molecules such as C4H10 are reformed into an alkene and H2. SO, for our case, i think its safe to say that A is the correct answer. :smile:

Exactly :biggrin: *_*
What assumption u made ? I wrote Carbon has Ar of 12 in mass spectrometry question
Original post by mr.holmes
ok so what do you expect the grade boundaries to be (lower than the January sessions)? :s-smilie:

I do hope so this paper was far more trickier than jan16
Original post by MrBioBombastic
Exactly :biggrin: *_*


but B also had two alkenes so couldn't that also be correct ( it also had hydrogen)
Original post by userk 12
but B also had two alkenes so couldn't that also be correct ( it also had hydrogen)


It supposed to have 1 alkene

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