The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

M1

A particle P of weight W newtons is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 5N is applied to P. The particle P is in equilibrium with the string taut and with OP making an angle of 25° to the downward vertical.

Edit: Find the tension in the string
(edited 7 years ago)
Reply 1
Avatar for Zacken
Zacken
22
Original post by Steelmeat
A particle P of weight W newtons is attached to one end of a light inextensible string. The other end of the string is attached to a fixed point O. A horizontal force of magnitude 5N is applied to P. The particle P is in equilibrium with the string taut and with OP making an angle of 25° to the downward vertical.

Edit: Find the tension in the string


Well, what have you tried?
Have tried drawing a diagram?
Reply 3
Avatar for Steelmeat
Steelmeat
OP
2
Original post by Zacken
Well, what have you tried?

so far from P i've drawn a little line with an arrow which has Mg on the end of it

Original post by ravioliyears
Have tried drawing a diagram?


Actually the diagram's on the piece of paper i have but i just couldn't be bothered to take a picture and post it on here...
Reply 4
Avatar for Zacken
Zacken
22
Original post by Steelmeat
so far from P i've drawn a little line with an arrow which has Mg on the end of it



Actually the diagram's on the piece of paper i have but i just couldn't be bothered to take a picture and post it on here...


I hope the Mg arrow is vertically downwards. Anyhow, resolve horizontally.
(edited 7 years ago)
Reply 5
Avatar for Steelmeat
Steelmeat
OP
2
Original post by Zacken
I hope the Mg arrow is vertically downwards. Anyhow, resolve vertically and horizontally.


yup i forgot to mention.

oh ok


Edit: I just seem to be getting this and this for horizontal and vertical

(<----) 5N
Vertically: Mg
(edited 7 years ago)
Reply 6
Avatar for Zacken
Zacken
22
Original post by Steelmeat
yup i forgot to mention.

oh ok


Edit: I just seem to be getting this and this for horizontal and vertical

(<----) 5N
Vertically: Mg


There are components of tension acting both horizonttally and vertically.
Reply 7
Avatar for Steelmeat
Steelmeat
OP
2
Original post by Zacken
There are components of tension acting both horizonttally and vertically.


I can't seem to see it in the diagram :/
Reply 8
Avatar for Zacken
Zacken
22
Original post by Steelmeat
I can't seem to see it in the diagram :/


Upload your diagram.

Tension is an arrow pointing along the string from P to O. It acts at an angle to the downward vertical. Resolve.
Original post by Steelmeat
I can't seem to see it in the diagram :/


Unsure what downward vertical meant but my attempt - image.jpg
Reply 10
Avatar for Steelmeat
Steelmeat
OP
2
Original post by Zacken
Upload your diagram.

Tension is an arrow pointing along the string from P to O. It acts at an angle to the downward vertical. Resolve.


Original post by Middriver
Unsure what downward vertical meant but my attempt - image.jpg


ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot :smile:
Original post by Steelmeat
ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot :smile:


No worries, is that what downward vertical meant btw?
Reply 12
Avatar for Steelmeat
Steelmeat
OP
2
Original post by Middriver
No worries, is that what downward vertical meant btw?


yes vertically down is another way of putting it
Resolve all the forces in two planes, you will always get a simultaneous or just a simple eq e.g tcos40=5gcos50
Reply 14
Avatar for Zacken
Zacken
22
Original post by Middriver
No worries, is that what downward vertical meant btw?


From O, draw a line passing through O, vertically downwards. The angle the string makes with this line is the angle with the downward vertical.
Original post by Zacken
From O, draw a line passing through O, vertically downwards. The angle the string makes with this line is the angle with the downward vertical.


Thanks
Reply 16
Avatar for Zacken
Zacken
22
Original post by Steelmeat
ahhhh i see i just didn't label the tension in the string as a letter oops thanks a lot :smile:


Original post by Middriver
Thanks


No problem.

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you