It's okay, you have another chance in paper 2, you can know learn from you mistakes. I got some questions wrong too. Hopefully the grade boundaries are going be low.
The gas left over was 30 , you didnt take into account what was in excess and in limited. Dont post answers if they're wrong.
Then why are you checking your answers with this mark scheme. There is no reason to be rude especially when I spent my time making this mark scheme to help others. Also, there are many people who told me that it was 50 so you may be the only one who's telling me it's wrong.
Then why are you checking your answers with this mark scheme. There is no reason to be rude especially when I spent my time making this mark scheme to help others. Also, there are many people who told me that it was 50 so you may be the only one who's telling me it's wrong.
I thought it would be obvious that it's not going to be 100% correct with "Unofficial" in the title, but that might just be me...
And, I don't think I said this before, but thank you for the time and effort to make this: much appreciated
Thank you! I really appreciate it. It took about 3 hours But it's always nice to know that people benefited from it. I'll hopefully make another for the paper 2. x
Thank you! I really appreciate it. It took about 3 hours But it's always nice to know that people benefited from it. I'll hopefully make another for the paper 2. x
That's bs. Paper 1 grade boundaries are never higher than 75%. Plus this was a new spec. Expect around 65% for an A for paper 1 and 70% for paper 2 which is bound to be easier.
Then why are you checking your answers with this mark scheme. There is no reason to be rude especially when I spent my time making this mark scheme to help others. Also, there are many people who told me that it was 50 so you may be the only one who's telling me it's wrong.
you should know that we all really appreciate the time and effort you put into this!! Helps me for sure and I know you must have other exams ) good luck for paper 2
you should know that we all really appreciate the time and effort you put into this!! Helps me for sure and I know you must have other exams ) good luck for paper 2
can anyone remember what they did for the barium and magnesium chloride question? I think I over complicated it
Two solutions used to get 35.5% - don't know if correct, but this it's what I got.
"1.052g total in the solid, from memory. BaSO4 is the ppt as it is insoluble in water. Mass of ppt was something around 0.78, I think. (137.3/233.4) is proportion of Ba in BaSO4. So, (137.3/233.4)*0.78 (or whatever it was) is mass of barium in ppt. This is therefore the mass of the barium in the BaCl2.
I used that to find the mass of the Cl in the BaCl2 using the fact that Cl ion is 1- and Ba ion is 2+. Therefore, you can find that the mass of the BaCl2 is 0.681 (from memory) and from that you can find the proportion of the MgCl2 in the solid at the start.
With this you get 35.5%"
"I can understand how you worked it out. I used another method by working out the number of moles using moles=mass/mr of baso4 then i wrote the equation bacl2+h2so4=baso4+2hcl and everything is a 1:1 ratio so the same moles of bacl2 were used. I worked out the mass of bacl2 from this using the mass=mr x moles. Then i took this away from the mass of both bacl2 and mgcl2 to work out how much mgcl2 there was. My answer was also 35.5%"