The Student Room Group

What are the most difficult M1 questions you have come across?

Preferably edexcel.

Spoiler

Spoiler

(edited 7 years ago)

Scroll to see replies

Q3 on this paper. It is great fun!

It tests almost everything you need to know for pulleys and scale pans
(edited 7 years ago)
Original post by Cryptokyo
Q3 on this paper. It is great fun!

It tests almost everything you need to know for pulleys and scale pans


Sounds fun, I'll give it a go now thanks.
Original post by KloppOClock
Preferably edexcel.

Also had good question here.

A ball is projected vertically upwards from a point OO with a speed uum/s. At the same time a second ball is dropped from a height of 40m vertically above OO. Given that the balls have the same speed when they collide, find the time at which they collide.
(edited 7 years ago)
Original post by Cryptokyo
Also had good question here.

A ball is projected vertically upwards from a point OO with a speed uum/s. At the same time a second ball is dropped from a height of 40m vertically above OO. Given that the balls have the same speed when they collide, find the time at which they collide.


Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds
Reply 5
Original post by KloppOClock
Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds

You could post your working and we can check it.
Original post by KloppOClock
Do you have the mark scheme for that, I tried to do it but I ended up with two times of -0.58s and -3.5 seconds

Solution in spoiler.

Spoiler

(edited 7 years ago)
Original post by notnek
You could post your working and we can check it.


Sure, I did it again and this time I got 10/7 seconds, although I'm not sure wha tthe correct solution is.
img023.jpg
Original post by Cryptokyo
Solution in spoiler.

Spoiler



ahh sound, i think i just messed up one of my substitutions in my first attempt.
@KloppOClock
Don't know if you have done them already but here is a link to tiered M1 papers. The gold ones are best.
Here is a link to some resources made by the user TeeEm.
Original post by KloppOClock
Preferably edexcel.
Reply 11
Original post by KloppOClock
ahh sound, i think i just messed up one of my substitutions in my first attempt.

Now you can do it you should pray that a similar question comes up in the real thing!

You would be part of a small minority who could do it.
Original post by Cryptokyo
Here is a link to some resources made by the user TeeEm.


That looks good.

Do you know where I can find a complete definition list for M1.
The only one I have is blank.

Untitled.png
Original post by notnek
Now you can do it you should pray that a similar question comes up in the real thing!

You would be part of a small minority who could do it.


ha if only, im just praying everyone messes up so they can lower the grade boundaries for me.
Original post by KloppOClock
Preferably edexcel.

Here is a paper I made ages ago. If you wanna have a go.

Ignore the definition question
(edited 7 years ago)
Original post by KloppOClock
That looks good.

Do you know where I can find a complete definition list for M1.
The only one I have is blank.

Untitled.png


Here is a powerpoint with all of that info
Original post by Cryptokyo
Here is a powerpoint with all of that info


Cheers, I tried to google for it before and couldn't find anything.
Original post by KloppOClock
Sure, I did it again and this time I got 10/7 seconds, although I'm not sure wha tthe correct solution is.
img023.jpg


why is it s-40 and not 40-s, s-40 will give you a negative distance?
Reply 18
Original post by Dominator1
why is it s-40 and not 40-s, s-40 will give you a negative distance?

Well that depends on which direction you take as positive.

Negative displacement is fine since it's a vector quantity.

But you're right that there is a mistake in the working. One of the displacement equations uses negative acceleration and the other uses positive.
Original post by notnek
Well that depends on which direction you take as positive.

Negative displacement is fine since it's a vector quantity.

But you're right that there is a mistake in the working. One of the displacement equations uses negative acceleration and the other uses positive.


the acceleration is fine, since one is accelerating and the other is decelerating. I was wondering about the distance because if it's the case of displacement being a vector then the two balls wouldn't have had the same velocity (because they're travelling opposite directions), they would have the same speed.
Then:
v=u-9.8t and -v=9.8t, making u=0
(edited 7 years ago)

Quick Reply

Latest