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[Official Thread] OCR MEI AS Mathematics 2016 (C1, C2 & S1)

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3x^-1/2 ii) -12x^-1 +c

when a=5 sum from u2 to u4 is 25
when a=6 sum from u2 to u4 is 0

r=2 d=3.5 difference is 768-33=735

Angle is 66.5~

y=sin(2x)

graph is translated (0, -3)

logs simplify to -3m

log question x=2.14

area of B is 1/2r^2(theta)-1/2a^2sin(theta)
a is 6root2cm~

trap rule A=22.8 V=1140

sub 4.8 into x, y is> 4.4 therefore wont fit

area according to model is 24 V=1200
sub 5+h and 5 into f(x) simplify to get 8+h
as h-->0 m=8
tangent is y=8x-25
area with axes is 39.0625
simplify logs to get straight line form with gradient b and y intercept log a
a~4.17 b~0.19

therefore y=4.17*10^0.19t

last question sub 4 into w viruses: 260.
(edited 7 years ago)
What was the question to which people got the answers 25 and 0? What did it ask you to do?
So disappointed- i know how to do all the questions that were on that paper except for 1 marker but when doing the paper, i made too many mistakes, just had no concentration. Even with the question asking for the equation of the sine curve on the graph i wrote y=sinx- missed the transformation completely...guess i'm retaking c2 next year.
Also. My integrated area was massive. 144cm^2. I redid the integration 100 times but I don't see my mistake.


Posted from TSR Mobile
Original post by ScalyJake
I also got this. Because the cubed was for the entire log, so you didn't bring it down to the front.


Yeah if you plugged in values for a and m into the calculator it worked out right
Was the equation for the sin graph y=sin(2x) ????????
Can we all agree there will be low grade boundaries as it was so hard this paper
Original post by Lucuniexet
Was the equation for the sin graph y=sin(2x) ????????


Yeah
Original post by tom476zf
yes got this :smile: not sure is its right though ?

Got same (-3m) pretty sure its right
Original post by Mr Moon Man
Yeah


Oh **** I wrote theta. Fml so many stupid mistakes


Posted from TSR Mobile
Original post by Qwertykeyboard15
Can we all agree there will be low grade boundaries as it was so hard this paper


Personally, i didn't find it hard at all. I still ****ed up that paper- though this wasn't due to difficulty, but to...i don't even know
Original post by Crozzer24
The log graph was awful, felt impossible to draw a best line of fit, ended up with y intercept of 0.6 and gradient 0.2 which seems way off


I got exactly the same
I put -m^3
I got y intercept of 0.58
Original post by Lucuniexet
for the simplifying log question i got -3m
is this familiar to anyone?!


*****t i just left it as -1^3m. do you think ill get marks for that
Reply 695
Original post by WuMyster
Also. My integrated area was massive. 144cm^2. I redid the integration 100 times but I don't see my mistake.


I got 144 as well but the answer was 24 apparently which makes a lot more sense as they should be similar but I don't know what I did wrong

I presume you were meant to x the fraction by the x values first and then integrate it.
Posted from TSR Mobile
Answer was -m^3 because the cube was for the whole log
Reply 697
Am I the only one who got 20 and 0
Did anyone get 5roo4/18 for q.3 b ??
Reply 699
Original post by Akhawais
Answer was -m^3 because the cube was for the whole log


you times indices across brackets giving you 3m

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