[Official Thread] OCR MEI AS Mathematics 2016 (C1, C2 & S1)

Scroll to see replies

Original post by Studious_Student

It shouldn't be 4. Talk me through your method.

Okay a is 5 right . 5/3 is 1.66666 so remainder 0.66666 0.6666x5 is 3.33, (3.3333/5) x5 is something else anyway it doesn't come to 25, no way , 4 point something

Reply 821

erinls2

Original post by The person

Everyone's saying that it was a hard paper. Everyone's complaining about the f(h+5) question. But if you actually revised properly and actually put in the effort, you could have answered these "impossible questions". You'll get the grade you deserve.

I found that question pretty simple because I revised that. I think it was tricky in the way that some of the questions were asked (like question 2 which I ****ed up. Also can someone confirm if you wrote the equation of the tangent in the form Y-y1=m(X-x1) would that still be right? I think I had something like y-15=8(x-5)

Reply 822

Studious_Student

Original post by ineedA

Okay a is 5 right . 5/3 is 1.66666 so remainder 0.66666 0.6666x5 is 3.33, (3.3333/5) x5 is something else anyway it doesn't come to 25, no way , 4 point something

That's not the remainder, that's the multiple that you need to multiply by 3 to get 5, think of it in the way of mixed fractions.

5/3 = 1 and 2/3, The two is the remainder here because it takes 1 lot of 3 and a remaining 2 to make the 5. Thus the remainder is 2. For the second part, it would be zero, because 6 can be completely divided by 3 to make 2/1 with no remainder needed.

Reply 823

ineedA

Original post by studious_student

that's not the remainder, that's the multiple that you need to multiply by 3 to get 5, think of it in the way of mixed fractions.

5/3 = 1 and 2/3, the two is the remainder here because it takes 1 lot of 3 and a remaining 2 to make the 5. Thus the remainder is 2. For the second part, it would be zero, because 6 can be completely divided by 3 to make 2/1 with no remainder needed.

shiiiiiiiiiiiiiiii, reckon ill get anny marks for my method, i know its unlikely -_-

(edited 7 years ago)

Reply 824

Studious_Student

Original post by ineedA

shiiiiiiiiiiiiiiii

Don't worry about it ahaha, I think a lot of people made stupid mistakes on this paper, I think I have lost around 8-10 altogether from them.

Reply 825

ineedA

Original post by Studious_Student

Don't worry about it ahaha, I think a lot of people made stupid mistakes on this paper, I think I have lost around 8-10 altogether from them.

do you have any idea whether or not the angle in the triangle was specified to 3 sig fig?

Reply 826

Studious_Student

Original post by ineedA

do you have any idea whether or not the angle in the triangle was specified to 3 sig fig?

By standard convention it is 3 significant figures. But I'm pretty sure they accept any reasonable form of rounding up (e.g. 2 Decimal places)

Reply 827

username2604219

What do you guys expect the grade boundaries to be?

Reply 828

NickC98

Original post by reoshinwho

What do you guys expect the grade boundaries to be?

I reckon low 50s for an A and then each grade below that the same distance apart as they usually do (5 marks between the grades?)

Reply 829

ghfijrwosbsv

Guys where can I find the unofficial mark scheme??

Reply 830

NickC98

Original post by ghfijrwosbsv

Guys where can I find the unofficial mark scheme??

https://docs.google.com/document/d/14jfC13frF0TU-6j2iKG2ldybTWfNex-Ndc0lcdM-wbM/edit

Reply 831

GO97

Original post by GO97

guys for that question with "f(h+5) - f(5)/h" could you assume that h represents the the change in x and so when when x=5 the change in x would be 0 and so u sub that into the simplified "h+8" to geit "0+8" which gives you 8, the answer???? or am i way off

can someone help confirm if i would get any marks for this^

Reply 832

e910b

It was roughly 260.7 so you were right to round up to 261. Also, you can't have a decimal of a flu case so it had to be a whole integer.

Reply 833

eLTee---

Original post by ineedA

Okay a is 5 right . 5/3 is 1.66666 so remainder 0.66666 0.6666x5 is 3.33, (3.3333/5) x5 is something else anyway it doesn't come to 25, no way , 4 point something

Incorrect, 5/3 is 1 remainder 2 therefore it would be 2x5 rather then the .6 recurring x5

Reply 834

xCoddi

Original post by Crozzer24

The log graph was awful, felt impossible to draw a best line of fit, ended up with y intercept of 0.6 and gradient 0.2 which seems way off

nahh dw I got the same

Reply 835

Anonymouse99

Original post by Studious_Student

So then wouldn't the answer be a = 12.7? Because the unofficial markscheme says a = 8.96

r^2/2 x Theta = a^2/2 x sin(theta)

Sub values in:

144/2 x 0.8 = a^2/2 x Sin (0.8)

(288/5)/sin (0.8) = a^2/2 ---> 80.2948504 = a^2/2

160.5897008 = a^2

a = 12.67 = 12.7 (3 sig figs) ?

That's what I got but I think it's wrong😞

Reply 836

NickC98

Original post by e910b

It was roughly 260.7 so you were right to round up to 261. Also, you can't have a decimal of a flu case so it had to be a whole integer.

But say in a question it's asking for the number of people with flu, you can't have 0.7 of a person with flu so surely you'd take the number of whole people (so 260)? You don't have 261 cases so can't use 261 as the number surely?

Reply 837

alevelnerd123

According to the unofficial mark scheme I think I got around 53 (give or take marks here or there depending on if i get method marks or if i missed some method marks), would that be a B?

Reply 838

pandasandpens

Original post by NickC98

All this rounding stuff is a pain haha. In s1, you're not allowed to round at all for an expectation, even when you can't have 0.7 of a person.
It's so annoying you lose marks for these things :s-smilie: