Oh is this how you do it? in the question it said it was travelling horizontally so i set the final speed (in y direction) to be 0 and found the vertical distance, then used trig to find PQ, has this method got any merit at all or have i just made it up? hahaha
I don't think it said it was travelling horizontally. I re read the question like 3 times thinking it must be travelling horizontally but I couldn't find anything that suggested it was (I had the projectile Q of 2015 in mind). Was I just illiterate? Lol
There's quad bike, car and truck. Bike is moving at 10ms^-1 due West. Relative to the bike is truck moving at bearing 340 (not sure) . The car is moving at 15ms^-1 due East. Relative to the car is the truck moving at bearing of 300 (I can't remember, someone let me know). Find the direction and velocity of the truck. [8]
Then another 8 marker afterwards that I didn't even bother reading
I don't think it said it was travelling horizontally. I re read the question like 3 times thinking it must be travelling horizontally but I couldn't find anything that suggested it was (I had the projectile Q of 2015 in mind). Was I just illiterate? Lol
Don't worry, you're not illiterate! It didn't say anything about it travelling horizontally as far as I can remember.
Since the angle was 45*, each shorter side would be the same length (I called it 'l', and you had to set x = 6 + l and y = l and solve it. Then you can work out what the length PQ is!
Just realised you mentioned this in an earlier comment!
There's quad bike, car and truck. Bike is moving at 10ms^-1 due West. Relative to the bike is truck moving at bearing 340 (not sure) . The car is moving at 15ms^-1 due East. Relative to the car is the truck moving at bearing of 300 (I can't remember, someone let me know). Find the direction and velocity of the truck. [8]
Then another 8 marker afterwards that I didn't even bother reading
There's quad bike, car and truck. Bike is moving at 10ms^-1 due West. Relative to the bike is truck moving at bearing 340 (not sure) . The car is moving at 15ms^-1 due East. Relative to the car is the truck moving at bearing of 300 (I can't remember, someone let me know). Find the direction and velocity of the truck. [8]
Then another 8 marker afterwards that I didn't even bother reading
Oh ok, i have done quite alot like that. Vectors would have been the nices way or combine the triangles geometrically(doesnt always work).
I wouldn't quite go that far aha. If there's more people like that around we can expect high boundaries. What did they get for the e < inequality for the projectiles?