M1 Edexcel Maths 8th June 2016 [MY ANSWERS] [COMPARE]

Hi, here are my answers to the paper sat today, not 100% sure if their entirely correct obviously but its up for comparison and discussion.

1)a) 104degrees
b) i) P : 400i + t(15i+20j)
ii) Q : 800j + t(20i-5j)
c) 640i + 640j

2) a) 20.6N
b) 15.45N

3) 3Ns

4)a) n/a diagram
b) T = 8.75s

5) Coefficient of friction = 0.73

6) i) d=1.2m
ii) m=42kg

7)a) 2.5i+2.5j
b) 13 ms^-1

8)a) T=11.76N
b) 16.6N at a bearing of 225degrees

Hope this helps.

Thanks, Keenan.

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Reply 1

JN17

Exactly the same as myself :biggrin:

, hopefully 100% then.
For 1b would you not have to combine the i&j components into one vector?

Got the same also

is this the edexel foundation 2016 paper 2 answers

Reply 4

keenafied

Original post by james5665

is this the edexel foundation 2016 paper 2 answers

No sorry

Reply 5

keenafied

Original post by JN17

Exactly the same as myself :biggrin:

, hopefully 100% then.
For 1b would you not have to combine the i&j components into one vector?

Haha yeah hopefully, time will tell! & im not too sure what you mean? you mean like in column vector notation? if so it wouldnt make a difference

Reply 6

JN17

Original post by keenafied

Haha yeah hopefully, time will tell! & im not too sure what you mean? you mean like in column vector notation? if so it wouldnt make a difference

b) i) P : 400i + t(15i+20j)
ii) Q : 800j + t(20i-5j)
As in replacing these answers with (400+15t)i + (20t)j and (20t)i + (800-5t)j, so collecting like components into one vector.

Reply 7

keenafied

Original post by JN17

b) i) P : 400i + t(15i+20j)
ii) Q : 800j + t(20i-5j)
As in replacing these answers with (400+15t)i + (20t)j and (20t)i + (800-5t)j, so collecting like components into one vector.

Oh I see, I dont think it will make a difference, in mark schemes for similar questions they do the same... you had to collect like terms for part c) to equate j components as it was due west, so they wouldnt mark you down anyway cos you proved you can still do it

Reply 8

youreanutter

Original post by keenafied

2b 5.15

Reply 9

keenafied

Original post by youreanutter

2b 5.15

you didnt take into acount acceleration? its still accelerating with the scale pan. If you stand in a lift and it doesnt move the force exerted on you is lower but when it accelerates upwards its greater..

Reply 10

RKM21

You may have got the first vector question slightly wrong. If it were (640i + 640j), Q would be East of P not West. So the i coords have to be in the negative direction - Thus (-640i+640j) would have been the answer. Well thats what I put anyway.

Reply 11

JN17

Original post by RKM21

t was equal to 32 I believe, at this time Q is at (640, 640) and P is at (880,640) if you plot these, P is further to the right than Q and hence Q is west of P.

Reply 12

keenafied

Original post by JN17

t was equal to 32 I believe, at this time Q is at (640, 640) and P is at (880,640) if you plot these, P is further to the right than Q and hence Q is west of P.

Yeah were right, he thinks its relative to the origin

Reply 13

musictagj

Original post by youreanutter

2b 5.15

I got that, because when I did F=ma I used the mass of both instead of one. You probably did the same

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Reply 14

james9990

hi does anybody know the answers for the maths edexel foundation paper 2 2016 or know anyone that does?

Reply 15

Rafeerahman

In number 3 would i gain at least 1 or 2 marks for finding out what the friction force acting on the particle was. i couldn't answer the question but just found out the friction

Reply 16

ODES_PDES

Paper anyone? :smile:

Reply 17

keenafied

Original post by Rafeerahman

In number 3 would i gain at least 1 or 2 marks for finding out what the friction force acting on the particle was. i couldn't answer the question but just found out the friction

It was out of 7, you might get around 2 marks because their was quite a bit you had to do after, including finding the acceleration, velocity after the collision.. and then the impulse calculation

Reply 18

Steliata

Original post by keenafied

Woop woop, same answers...

Although I left 5 as 3sf and rounded 8a to 3sf meaning that b was 16.7N, which I said was at 45 degrees (with a diagram) Hopefully shouldn't get penalised for that...

Reply 19

TSRPAV

Does anyone know how many marks I'd lose if I got the method correct but values wrong? E.g for moments question I got d=1.2m but to find m I accidentally used 1.2 when doing moments about A, the method was correct but due to accidentally using this my answer was wrong, I also did the same for implies question, got method correct but my value for deceleration was wrong as I did a=-1/8*0.4*g, completely forgot its 0.4a is equal to muR but everything else was fine on these examples, so how many marks would I roughly lose? Thanks

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