I've been looking for a proof of this but its impossible to find one. Ive started with the fact that E=QV therefore dQ/dt=d(E/V)/dt dE/dt= power = P= IV but I'm stuck with derivative of voltage. I know quotient rule will help.
I've been looking for a proof of this but its impossible to find one. Ive started with the fact that E=QV therefore dQ/dt=d(E/V)/dt dE/dt= power = P= IV but I'm stuck with derivative of voltage. I know quotient rule will help.
thanks
Instead of using calculus, you could just use normal equations: E=QV and tE=P=IV Equate the two equations for E:
tE=tQV=P=IV
Cancel the voltages off both sides after combining: tQV=IV→tQ=I