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C4 Parametric cartesian equation help needed!

First one I'm stuck on...

1) x = 4t + 3 , y= 16t(t+1)

Find a cartesian equation

for my answer I got (x - 3)(x - 2) actual answer is (x - 3)(x + 1)

2) x= t + 1/t^3 , y= t^3 + 1/t^3

answer is x^3= y + 3x

Find a cartesian equation.
Reply 1
Original post by AndyOC
First one I'm stuck on...

1) x = 4t + 3 , y= 16t(t+1)

Find a cartesian equation

for my answer I got (x - 3)(x - 2) actual answer is (x - 3)(x + 1)

2) x= t + 1/t^3 , y= t^3 + 1/t^3

answer is x^3= y + 3x

Find a cartesian equation.


t=(1/4)(x-3)

Sub that in to the y equation
Reply 2
Original post by Shumaya
t=(1/4)(x-3)

Sub that in to the y equation


yeah i see what I've done now just an algebra mistake, thank you! could you help with the second one please?
Reply 3
Original post by AndyOC
yeah i see what I've done now just an algebra mistake, thank you! could you help with the second one please?


I'm working on it :smile:
Reply 4
Original post by Shumaya
I'm working on it :smile:


Any luck with that question?
Reply 5
Original post by AndyOC
Any luck with that question?


Nope haha. Just hoping that the parametric equations in the exam are nicer!
(edited 7 years ago)
If you can't do it tonight I'll do it tomorrow morning for you :P
Reply 7
Original post by Shumaya
Nope haha. Just hoping that the parametric equations in the exam are nicer!


Yeah hope so!
Reply 8
Original post by nobodycarescarla
If you can't do it tonight I'll do it tomorrow morning for you :P


If you could that would be great :smile:
Original post by AndyOC
If you could that would be great :smile:


Hey can you double check for me
2) x= t + 1/t^3 , y= t^3 + 1/t^3 that this is the right question? I cant understand how they got the answer, it doesnt seem right
Original post by nobodycarescarla
Hey can you double check for me
2) x= t + 1/t^3 , y= t^3 + 1/t^3 that this is the right question? I cant understand how they got the answer, it doesnt seem right


What was your answer?
Reply 11
Original post by nobodycarescarla
Hey can you double check for me
2) x= t + 1/t^3 , y= t^3 + 1/t^3 that this is the right question? I cant understand how they got the answer, it doesnt seem right

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Question and answer
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Hey you use your answer to part a
(edited 7 years ago)
Original post by AndyOC
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Question and answer

Ah thankyou! I mis understood what you ment :')
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Reply 14
Original post by nobodycarescarla
Ah thankyou! I mis understood what you ment :':wink:
20160611_151719.jpg


Brilliant thank you!:smile:

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