For most processes I have some kind of temperature down - don't know how reliable they are. Like for the nitration of benzene I have 60 degrees written down.
nope only temperature affects the value of the rate constant, K. Increase temp and K increases, decrease temp and K decreases. Nothing else affects.
pressure affects it for sure... if you increase the pressure in a reaction but you don't change the temperature or concentrations, does the rate go up? (i hope you're thinking yes) so for rate = K[a]if rate is going up, then one of K, [a], or must be going up.which one is it?
How can any of the molecules be spectrum IV then because can't they all lose 1 hydrogen? The answer is meant to be molecule B for spectrum IV but can't it lose a hydrogen from "CH3"?
Yeah but the are talking about 'major ' peaks above an m/z of 100. Those probably could occur but its probably not as abundant. The reason the H breaks off from the CO Group is because the CO+ Ion (acylium ion) has a stability due to the delocalisation of the positive charge across the CO which increases its abundance and likelihood of formation.
Towards the end of the link below, it goes in a bit more detail:
Yeah but the are talking about 'major ' peaks above an m/z of 100. Those probably could occur but its probably not as abundant. The reason the H breaks off from the CO Group is because the CO+ Ion (acylium ion) has a stability due to the delocalisation of the positive charge across the CO which increases its abundance and likelihood of formation.
Towards the end of the link below, it goes in a bit more detail:
dividing the moles by the volume 1.005dm-3 (since new total) is what you be doing, try it with this and without you'll get the same answer, but i always use volumes just in case
dividing the moles by the volume 1.005dm-3 is what you be doing, try it with this and without you'll get the same answer, but i always use volumes just in case
question 4d... chemical shift 4.13 can only be an OH group surely??? :/
That question is a bit eh. 4.13 is pretty much 4.1 which can be used and not the O-H group. The question also states that Compund X has an ester and ketone group in it so no OH is present. The alkyl group in that case is CH2CH3