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Potential difference over a component = work done?

Hi everyone, does the potential difference over a component equal the work done across that component by the power supply? (excluding energy lost via heating)

Thanks! :smile:
it equals work done divided by charge p.d= workdone/charge
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atomc19
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Original post by tomiakande
it equals work done divided by charge p.d= workdone/charge


Oh great, thanks! :smile:

That makes them directly proportional then. How do you calculate charge?
Original post by thomas-cowley
Oh great, thanks! :smile:

That makes them directly proportional then. How do you calculate charge?


charge = current x time no problem:h:

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