Aqa june 2016 chemistry unit 4

Well I guess that went badly... 50 for a C hopefully?
Anyone make a markscheme?

Protonated b?
Orders? 1 and 0?
Ka not for acids because completely dissociated?
2nd last question nice empirical formula
Last question deadly - 9 marks for a primary alcohol

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Reply 1

shellypatel2

i'm guessing the end N was protonated due to the inductive effect, making the lone pairs more prominent, hence a better base.
I got 1st for D and 2nd for E (Is this Question 6)

Reply 2

Angel95726

Original post by shellypatel2

i'm guessing the end N was protonated due to the inductive effect, making the lone pairs more prominent, hence a better base.
I got 1st for D and 2nd for E (Is this Question 6)

Yeh i got 1st and 2nd order aswell,

Reply 3

Angel95726

That paper was honestly really bad so many hard questions.... hopefully the grade boundaries will be really low

Reply 4

Wolfeylever

Think you had to say the electrons in a are delocalised into the benzene ring too :/ but I don't know the paper was crazy

Reply 5

Rid123

Anyone else get a cyclic compound when ethanal reacts with ethan-1,2-diol?

Reply 6

DiluteNitricAcid

anybody brave enough to scan in a drawing of/describe the structure they got for the last 9 marker?

Reply 7

matty9

[video="youtube;RXthYHvOSn0"]https://www.youtube.com/watch?v=RXthYHvOSn0[/video]

Hitler reacts hahaha

Reply 8

Angel95726

Original post by Rid123

Anyone else get a cyclic compound when ethanal reacts with ethan-1,2-diol?

I didnt :/ i got ch3-coo-ch2-ch2oh i rushed that question coz i left it till the end :s-smilie:

Reply 9

Z_A101

I got a tertiary alcohol on the last question but realised that it was supposed to be a primary/secondary right at the end, reckon i'd get chemical error on it even though I identified the groups correctly just didn't put them together right

Reply 10

Rid123

Original post by Z_A101

I did the exact same thing ahah, but we will get some method marks for identifing certain groups i think.

Reply 11

Z_A101

Original post by Rid123

I did the exact same thing ahah, but we will get some method marks for identifing certain groups i think.

I hope so buddy xD

Reply 12

kimmii97

Did anyone have a go at the question where you had to suggest why the salt of lidocaine was preferred over lidocaine itself?

Reply 13

UmarChowdhury

I got 2 and 0 but hey its all over.

Reply 14

UmarChowdhury

Original post by kimmii97

Did anyone have a go at the question where you had to suggest why the salt of lidocaine was preferred over lidocaine itself?

Yes. In the previous question it was established that one of the nitrogen atoms were protonated in lidocaine hydrochloric acid.

Being protonated, and water in blood being polar, lidocaine hydrochloric acid will be soluble in the blood (hence preferred for medical use.)

(edited 7 years ago)

Reply 15

Jonnyss

Original post by Angel95726

That paper was honestly really bad so many hard questions.... hopefully the grade boundaries will be really low

Like what apart from the last one?

Reply 16

big-ben

for question 9 CH3-O-CH2-CH2-C(CH3)2-OH is what i got, 5 H N.M.R things, and they fit all of the criteria on the table

Reply 17

kanelikesfrogs

What was the test to distinguish the acyl chloride from that other compound? I put water because it would react with acyl chloride and make steamy fumes (hcl) but they both had a chlorine atom on them I think? Anyone shed some light?