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STEP 2016 Solutions

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Reply 20
Original post by student0042


I left my answer was ((7^7 + 1)^3 - sum of 7's)((7^7 + 1)^3 + sum of 7's). :redface:
Original post by Zacken
I left my answer was ((7^7 + 1)^3 - sum of 7's)((7^7 + 1)^3 + sum of 7's). :redface:


That probably would have been better. Oops.
Reply 22
Original post by student0042
That probably would have been better. Oops.


I don't think it would have... I'll probably get docked a mark or two. Ahhhh.
Original post by Zacken
I don't think it would have... I'll probably get docked a mark or two. Ahhhh.


Really? Did it want the answer like this? I don't remember what form it said, I thought it was just some form with 7^7 in it.
Reply 24
Original post by student0042
Really? Did it want the answer like this? I don't remember what form it said, I thought it was just some form with [math] 7^7 [/math] in it.


It said "factors written as a sum of various powers of 7", I'm not sure if (7^7 + 1)^3 counts. :frown:
Original post by Zacken
It said "factors written as a sum of various powers of 7", I'm not sure if (7^7 + 1)^3 counts. :frown:


I'm not sure either, but (7^7 + 1)^3 looks a lot nicer.
Original post by Zacken
Just attaching it in big size for you:



(side note, this was a gift question!)

(other side note, I forgot sin -4 was positive...)


How many marks do you recon lost for not including where it was discontinued? I put the y values but I didn't get what it meant.. Which was kind of stupidly obvious now... That's in all parts I didn't do it
(edited 7 years ago)
Reply 27
Original post by rohanpritchard
How many marks do you recon lost for not including where it was discontinued? I put the y values but I did get what it meant.. Which was kind of stupidly obvious now... That's in all parts I didn't do it


Probably 4/5 marks?
Hey Zacken, what do you think is roughly going to be a grade 2 based on this year's paper difficulty? Thanks
Reply 29
Original post by kelvin1338
Hey Zacken, what do you think is roughly going to be a grade 2 based on this year's paper difficulty? Thanks


My honest opinion is that it'll be about 62 for a 2.
I did not do as well on this as I wanted aha. I need a 2 for my insurance which I think I should have managed, but I wanted a 1. Then again it's probably my fault for not doing enough practice for it...

On question 2 I goofed on part ii and couldn't work out what to substitute oops, and on question 3 I didn't include the dots for the discontinuity...
STEP 1 Q9 solution. I couldn't remember for SURE which way round they put the coefficients of friction but I'm pretty sure it's this way, doesn't actually make any difference for the answer anyway. I realised I got the last bit wrong in the actual exam because I didn't account for the force due to friction at the rail also changing direction (I only changed it at the wall) -_-. This is correct here though.
(edited 7 years ago)
Reply 32
Original post by Mathemagicien
Yay! That's the answer I got. :biggrin:

Btw, e simplifies to sqrt 5 - 2


Yep, couldn't be bothered in the exam though. As it is, I spent 15 minutes checking everything because I was convinced my answer wasn't correct, with all the sqrt(5) shiz.
Original post by Zacken
Yep, couldn't be bothered in the exam though. As it is, I spent 15 minutes checking everything because I was convinced my answer wasn't correct, with all the sqrt(5) shiz.


I did exactly the same, thought it would be a nice fraction so spent ages checking.


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Original post by Ecasx
STEP I 2015 Q12

(i) Alice tosses a fair coin two times and Bob tosses a fair coin three times. Find the probability that Bob obtains more heads than Alice.

(ii) Alice tosses a fair coin three times and Bob tosses a fair coin four times. Find the probability that Bob obtains more heads than Alice.

(iii) Alice and Bob both throw a fair coin n times. The probability that they obtain an equal number of heads is p1, and the probability that Bob obtains more heads is p2. If Bob now throws the coin n+1 times, find the probability (in terms of p1 and p2) that Bob throws more heads than Alice. Hence generalise your results to parts (i) and (ii).

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Oh damn that's quite an easy question. :smile:
Reply 35
Q7

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(edited 7 years ago)
Original post by Zacken
I left my answer was ((7^7 + 1)^3 - sum of 7's)((7^7 + 1)^3 + sum of 7's). :redface:


what do you think the mark weighting will be for parts 1 and 2
Original post by smartalan73
STEP I, Question 3


graphs 001.jpg


I stupidly marked the coordinates of the points at the beginning and ends of the horizontal lines. Given that I still got all of the shapes right, how many marks would I have lost do you think?
Original post by jahovasfitness
I stupidly marked the coordinates of the points at the beginning and ends of the horizontal lines. Given that I still got all of the shapes right, how many marks would I have lost do you think?


If you still got the coordinates right, I don't see why you should lose any marks?
Reply 39
Original post by smartalan73
If you still got the coordinates right, I don't see why you should lose any marks?


Agreed.

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