AQA Maths FP1 - 15 June 2016 [Exam discussion]

Yes it was 1 because they were recipricals of each other and recipricals multiply to 1

For the alpha & beta question, did anyone get 14/14 = 1 for the product on the last part? 1 just seems like an odd answer lol

Yeah I got that but I cant remember if I put 7 or 4 (by accident) as the cofficent of x^2

I mean part d where the question asked P is imaged at point [0,-4] then something to do with the matrix A^2 and reflected on the line X+root3Y=0. Did anyone else get something like 3root2, 2?

Just some big parts where I have just messed up.
- Standard alpha and beta, ended up getting 7x^2 - 4x + 7=0 something like that

- Linear laws, gradient = -0.4, value of a is 10^intercept, value of b is 10^-0.4

- General solution gave npi + pi/2 and npi + pi/3
So tanx can only have pi/3

- Matrices enlargement sf 4 for A^2 ??? then I ended up doing simultaneous to find the coordinates to plot to (0,-4) ??
I hope I've read the question right :/ I think i've got my reflection matrix wrong ffs
It was in the line y=-1/root 3 x so y=tan(-30)x and which is tan(150) so I had to find cos(300) and sin(300) lol wth
so I got 1/2 & -root3/2, then simultanous equations to solve for x & y. basically I've wrecked that question
Because my working out is a load of bs.
Dropped idk how many marks, will be error carried forward for second part though?
dropped 5 marks probably on this question

- parabola and show a=2 was fine, but second part I've messed up forgot to realise that it was translated (2, 3) ?? something like that y^2=4ax -> (y-3)^2=4a(x-2) and it passes through 4,7. so 16=8a a=2
you had to show b^2-4ac<0 with ky=x but since its translated k(y-2)=(x-2)
lol i give up thats like another 5 marks gone.

- series questions show that was fine, second part was to show 4 linear factors
I didn't finish that one ffs but got something with (2n+1)(2n-1)
hopefully I've only dropped 3 marks on this idk

-Complex question I worked out p=+-4 and i worked out sum and product
I got two equations for q lol idk wrecked that
You had to explain why q=-1 for two marks, so I said something like because it needs to be a real coefficient or something like that. And when q=-1 it gets rid of all the imaginary parts?? :/

-asymptotes y=0, x=2, x=-1/2 ??? something like that
-sketch,
-form cubic inequality with intersection then stuck it into my calculator go like x=0, x=1, x=5/2 for my critical values
I can't remember.

Overall id be lucky to get an A
~59/75 I think

"You had to explain why q=-1 for two marks, so I said something like because it needs to be a real coefficient or something like that. And when q=-1 it gets rid of all the imaginary parts?? :/"

I put that when q=-1 it eliminates imaginary parts too but it was literally a guess LOL

For the conics question, solving the possible values of k, did anyone get
-2<k<0.5 (or -0.5<k<2 cant remember which way around i had my numbers)

What was the exact question? I might be able to help

I can't remember exactly :/ But there was an equation with " i + qi " in it and it asked to explain why q must be -1 for it to be real

So that the imaginary parts vanish I should imagine.

Apart from a few odd (and very badly worded, I must say) questions the paper was easier in comparison to the last couple of years'.

q was real in the first part of the question, but when 'p is real', is it real as well as or instead of q?!

Just some big parts where I have just messed up. ~59/75 for an A imo

- Standard alpha and beta, ended up getting 7x^2 - 4x + 7=0 something like that

- Linear laws, gradient = -0.4, value of a is 10^intercept, value of b is 10^-0.4

- General solution gave npi + pi/2 and npi + pi/3
So tanx can only have pi/3

- Matrices enlargement sf 4 for A^2 ??? then I ended up doing simultaneous to find the coordinates to plot to (0,-4) ??
I hope I've read the question right :/ I think i've got my reflection matrix wrong ffs
It was in the line y=-1/root 3 x so y=tan(-30)x and which is tan(150) so I had to find cos(300) and sin(300) lol wth so I got 1/2 & -root3/2, then simultanous equations to solve for x & y. basically I've wrecked that question
Because my working out is a load of bs.

Edit: I've just seen in the textbook lol reflection in y=-x/root3 is the same as a reflection in y=tan150x
which is (cos300, sin 300) (sin300, -cos300) WAIT THERE. MAYBE IM ONTO SOMETHING
Dropped idk how many marks, will be error carried forward for second part though?
dropped 5 marks probably on this question

- parabola and show a=2 was fine, but second part I've messed up forgot to realise that it was translated (2, 3) ?? something like that y^2=4ax -> (y-3)^2=4a(x-2) and it passes through 4,7. so 16=8a a=2
you had to show b^2-4ac<0 with ky=x but since its translated k(y-2)=(x-2)
lol i give up thats like another 5 marks gone.

- series questions show that was fine, second part was to show 4 linear factors
I didn't finish that one ffs but got something with (2n+1)(2n-1)
hopefully I've only dropped 3 marks on this idk

-Complex question I worked out p=+-4 and i worked out sum and product
I got two equations for q lol idk wrecked that
You had to explain why q=-1 for two marks, so I said something like because it needs to be a real coefficient or something like that. And when q=-1 it gets rid of all the imaginary parts?? :/
z^2 + (4 + i +qi) z + idk =0so if q=-1(4+i-i)z so 4z something like that

-asymptotes y=0, x=2, x=-1/2 ??? something like that
-sketch, (x-1)/(x-2)(2x+1) something like that ??? I can't remember
-form cubic inequality with intersection then stuck it into my calculator go like x=0, x=1, x=5/2 for my critical values
I can't remember.

Overall id be lucky to get an A