C3 Maths A2 AQA 2016 (unofficial mark scheme new)

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ok ive made corrections

you use area of triangle = 1/2ab and bobs ur uncle

**** me are you serious? I did that at first with the wrong co-ordinates, got the right co-ordinates then assumed that method was still wrong. I thought E^x would be curved but now I realise then it woudn't be a ****ing triangle

I'm an arse

I guess that doesn't matter, I'd need another 15 marks probably to get an A* and to get an A overall I need C's in the other papers. A* would be out of reach regardless

(edited 7 years ago)

Reply 41

username2592579

yeah lol from O to A is a straight line
so is O to B so that forms a right angle
hence triangle

Reply 42

Peter Wilkinson

Original post by Sirelis

fak i got like 40 if I'm lucky

Same lmao

Reply 43

irMike

Original post by beanigger

yeah lol from O to A is a straight line
so is O to B so that forms a right angle
hence triangle

Honestly I thought that the first time, then when I saw it was getting nowhere I changed my mind. Looking through this mark scheme I got between 45 and 49, Having gotten 70+ on every past paper I've done in the past week. Can't believe this.

Reply 44

alextp5498

Any ideas as to what the grade boundaries will be like ? considering last years was 57 for an A, hopefully this years will be lower.

Reply 45

username2592579

roughly the same, but it will not be lower than 55 for an A

Reply 46

Parhomus

Original post by irMike

Well I think I got from around 60-64 assuming the worst; but that's assuming the way im distributing marks in questions I got wrong is correct; so that I get the method marks at least. By the way for the question leading up the sinx=2/3 or something; was that a question with a quadratic equation where you had to reject one of the values or am I remembering wrong. AND WHAT WAS THE QUESTION ITSELF????????

Reply 47

Anon998

2e - integrate 5 then do your answer minus the answer from simpsons rule

Reply 48

Parhomus

Original post by Anon998

2e - integrate 5 then do your answer minus the answer from simpsons rule

For that one you just get the answer from the previous question - 5(1.7-0.5); and since that is the value of the integral of the negative x^x you just change signs and it gives you 1.51 or something.

Reply 49

matty9

Original post by Anon998

2e - integrate 5 then do your answer minus the answer from simpsons rule

Ahhh that's how you do it, I just did the simpsons rule again haha, for 2 marks will this even gain anything?

Reply 50

username2592579

well aqa maths dont uusally give a lot of follow on marks, its usually just one M1 mark for applying a certain method so make sure you add it up right

Reply 51

Parhomus

Original post by matty9

Ahhh that's how you do it, I just did the simpsons rule again haha, for 2 marks will this even gain anything?

Not sure because I think it said using the previous answer but I don't remember jack ****.

59 a*
53 a
47 b
41 c

Original post by Parhomus

Not sure because I think it said using the previous answer but I don't remember jack ****.

Yes it said 'hence find an estimate' but wasn't sure what to do so did simpsons ruls again.

Reply 54

Parhomus

Original post by beanigger

well aqa maths dont uusally give a lot of follow on marks, its usually just one M1 mark for applying a certain method so make sure you add it up right

Do you remember the question for the one about the area of the triangle :C. I managed to get m and n=3 but I don't know how. I just wanna check what I messed up to see how many marks i lost.

Reply 55

Sayless

b) find gg(x) g(x) = 1/x therefore gg(x) = x [2]

I got gg(x) = x^4
as g(x) = 1/x^2

can you double check that one, not sure it's right

Reply 56

Parhomus

Original post by Sayless

b) find gg(x) g(x) = 1/x therefore gg(x) = x [2]

I got gg(x) = x^4
as g(x) = 1/x^2

can you double check that one, not sure it's right

fg(x) means f(g(x)) so when you got the equation; g(x) wouldn't be 1/x^2 it would 1/x because the x in the f(x) just means the input and so g(x) could only be 1/x. I understand why it would make sense for it to be 1/x^2.

Reply 57

matty9

Original post by Sayless

b) find gg(x) g(x) = 1/x therefore gg(x) = x [2]

I got gg(x) = x^4
as g(x) = 1/x^2

can you double check that one, not sure it's right

I put the same but it's wrong.

g(x) was 1/x because I forgot that in functions the entire x is replaced so it wasn't 1/x^2 can't remember the question so kinda hard to explain.

Reply 58

alikhaliq

Original post by matty9

Yes! I got sinx = 2/3 then used pythag to get cosx = root5/3

Then subbing these into the orginal equation gave me -1/5 root 5 but I don't know how correct that is