You can do (sec(x)- tan(x)) x ((secx+tanx)/secx+tanx)=-5 Then you get (sec^2x-tan^2x)/secx+tanx =-5 sec^2x-tan^2x=1 so u get 1/(secx+tanx)=-5 So secx+tanx=-1/5
This is exactly what I put in the exam, I'm sure about x=-21.3 but not the other one as desmos is only showing one solution
This is exactly what I put in the exam, I'm sure about x=-21.3 but not the other one as desmos is only showing one solution
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Your answers are correct for the values of x, I messed up on this one and didn't include a value of x before i did the +70 then /2 so I only got the -88.7
Your answers are correct for the values of x, I messed up on this one and didn't include a value of x before i did the +70 then /2 so I only got the -88.7
Thing is when you put x=-88.7 into the original equation it doesn't work? It gives you -0.2 instead of -0.5 so I feel like there's something wrong but I just can't find it
Thing is when you put x=-88.7 into the original equation it doesn't work? It gives you -0.2 instead of -0.5 so I feel like there's something wrong but I just can't find it
-88.7 doesn't work, I'm confused as to why that's the case though. It gives you a different tan value...
-88.7 doesn't work, I'm confused as to why that's the case though. It gives you a different tan value...
Maybe it's outside the domain? Was it -90<x<90 or have I remembered it wrong? Cause -247.4, which -88.7 comes from, is definitely a solution of cosx=-5/13 between -250 and 110, which I got from applying 2x-70 to the original domain
fg(x) means f(g(x)) so when you got the equation; g(x) wouldn't be 1/x^2 it would 1/x because the x in the f(x) just means the input and so g(x) could only be 1/x. I understand why it would make sense for it to be 1/x^2.
Maybe it's outside the domain? Was it -90<x<90 or have I remembered it wrong? Cause -247.4, which -88.7 comes from, is definitely a solution of cosx=-5/13 between -250 and 110, which I got from applying 2x-70 to the original domain
Yep I got it too, it was definitely -90<x<90, strange.
Yep I got it too, it was definitely -90<x<90, strange.
-88.7 is a solution to the equation sec(2x-70) PLUS tan(2x-70)=-0.2, maybe that's got something to do with it? Was adding the equations that you're given to find secx (i.e. cosx) wrong?
Yep I got it too, it was definitely -90<x<90, strange.
Dunno if it helps anyone but 1.3 degrees works which is what I put down, I too got -88.7 but tried it and saw it didn't work so played around with it and got 1.3 which worked.
-88.7 is a solution to the equation sec(2x-70) PLUS tan(2x-70)=-0.2, maybe that's got something to do with it? Was adding the equations that you're given to find secx (i.e. cosx) wrong?
Nope it isn't wrong, they got you to find that before you even did the second part. Everyone I've spoken to did what we did. If someone can find a valid reason or explanation as to what the actual solution was I'd be grateful.
Dunno if it helps anyone but 1.3 degrees works which is what I put down, I too got -88.7 but tried it and saw it didn't work so played around with it and got 1.3 which worked.