"...the earth terminal is connected to the metal casing so that the current goes through the earth wire instead of causing an electric shock." - Bitesize

Reply 85

Monsor

Original post by SmithAmelia

It was the earth wire

No it is the live wire

Posted from TSR Mobile

Reply 86

SmithAmelia

Original post by zeldor711

Correct, but it was 0.8 because the wave had to travel there and back

Yes therefore you have to divide this by 2 to get the real distance right, and not the double distance right?

Reply 87

SmithAmelia

Original post by Monsor

No it is the live wire

Posted from TSR Mobile

How? Bitesize says it's the earth wire?
Could you explain it please, thanks

Reply 88

ruadb0y

Original post by zeldor711

Correct, but it was 0.8 because the wave had to travel there and back

I got 0.9 for the ultrasound one..?

Reply 89

YAY GCSE

[QUOTE="user2k16;65865361"]yah due to faster speed[/QUOTE

If u are talking about the drag question then the drag increased because it was going faster

Reply 90

Katwamba01

Original post by SmithAmelia

It was the earth wire

It was live wire. I wrote that myself too.

Reply 91

Syyed_

Original post by SmithAmelia

How? Bitesize says it's the earth wire?
Could you explain it please, thanks

Well the live wire is the wire thats connected to the fuse. The fuse is to the right and the live wire is to the right soo yh. The live wire also has a brown colour

Reply 92

user2k16

what did everyone get for the universe questions

Reply 93

YAY GCSE

Original post by Katwamba01

It was live wire. I wrote that myself too.

It was 100% the live wire! :smile:

Reply 94

YAY GCSE

Anyway I still found that hard :frown:

not taking it next year but was looking at an A. Not to confident now

Reply 95

Ethanf8200

Original post by TrumpIsFancy

should be something like 40 for an A* as it was 41 for A* in 2013 and it was easier imo

Yeah but you know how AQA are nowadays lol

Reply 96

trollface54

For the ultrasound q wasn't it the speed between detector a and b
So because they give you the distance 4.0 cm you divide by 2 and convert into metres
Then divide by 50*10^-16
I got 4oom/s

Reply 97

Monsor