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OCR (non mei) M1 Friday 17th June 2016

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Original post by daniellon
Cosine rule in the formula booklet?


Yep
What was the tension before P was released?
Original post by daniellon
What was the tension before P was released?

O.2g = 1.96?
My answers:
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76
Original post by Furthermaths100
My answers:
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76


Please could you help by putting these into the community MS?
Original post by Furthermaths100
My answers:
Distance: 10, time 1.43
a=6.8
3, 1.25
82.7
82.8
0.918, 48.6
6
3.75
4.75
12, 16.3
2.06 (east)
1.96, 1.81
3.64
1.96?
10
3, 25 (as shown)
6.76

I got 2.37 instead of 1.96
Original post by Parallex


Ahh, fair enough. Looks like I pictured the resultant force wrongly...
Original post by Parallex
your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)
Original post by physicskid123
your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)


It isn't wrong..
Original post by Parallex
It isn't wrong..


it is
For question 5 I said the direction is to the right. Can I get away with it
your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)

- You're a moron.
Reply 33
any grade boundary predictions?
Reply 34
What are people predicting for grade boundaries?
look it's cos a = (4^2 + 4^2 - 6^2) / 2*4*4 so cos a = -.125 and so a is 97.18
Original post by Parallex


That equation isn't correct.

You did b^2 + c^2 - a^2/ -2bc but there shouldn't be a minus
It should be just 2bc
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(edited 7 years ago)
Original post by daniellon
For question 5 I said the direction is to the right. Can I get away with it

I did too
What was the total mark for the question with the 2 4N forces because I got that whole bit wrong
Just a quick question for question 4 part iii. In the unofficial mark scheme it mentioned that it had already been verified. However in the question it said that after B collides with CD that there are no more collisions after this point. This means that surely B can not have a velocity of zero as A would then collide with B. Therefore shouldn't the velocity of B be at least greater than 4ms^-1 (which was the previous speed of A).

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